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Levart [38]
2 years ago
15

Please help I will give brainliest!

Mathematics
2 answers:
vladimir2022 [97]2 years ago
4 0

Answer:

The correct answer is B. 30.

Step-by-step explanation:

538 - 509 = 29

Since we need to round this to the nearest tens place, that means we need to round it to 10, 20, 30, etc.

When rounding a number, you look at the last number in it. If it is a <em>5 or higher</em>, you <em>round up</em> the number before it by 1. If it is a <em>4 or lower</em>, the number before it<em> stays the same</em> and the <em>lowest number</em> turns into a 0.

Since 9 is <u><em>higher</em></u> than 5, the 2 in 29 will turn to a 3, and the 9 will turn into a 0.

Therefore, the correct answer is B. 30.

Hope this helps! :D

Gwar [14]2 years ago
3 0

Answer:

30

Step-by-step explanation:

538 = 540

509 = 510

40 - 10 = 30

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There are 9 whole numbers in between 20 and 30 
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The discount place on three computer are 4/5 1/4 and 3/10 which one has the highest price
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Answer:

4/5

Step-by-step explanation:

<u>4/5 = 80%</u>

1/4 = 25%

3/10 = 30%

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Takashi Caldwell has health insurance that pays 80 percent of coverage charges after a $150 deductible. She received a statement
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Subtract the deductible from the total:

350 - 150 = 200

Takashi then needs to pay 20% of what is left.

200 x 0.20 = 40

Takashi has to pay the 150 deductible plus 40 for a total of $190

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Suppose we write the numbers $1,2,3,4,5,6$, and then color each number red or blue. The coloring is called factorific if there i
Oxana [17]

Answer:

The probability that his coloring is factorific is 0.28125

Step-by-step explanation:

For calculate the probability is necessary to identify the total number of ways to color the six number. This can be calculate with the rule of multiplication as:

2*2*2*2*2*2=64

Because we have 2 options to color every number.

For know the number of ways in which the coloring is factorific, first we need to identify the divisors of each number:

1: the divisor is 1

2: The divisors are 2 and 1

3: The divisors are 3 and 1

4: The divisors are 4, 2 and 1

5: The divisors are 5 and 1

6: The divisors are 6, 3 and 1

From these information we analyse that for made a factorific coloring, is necessary that the number 1 is color blue. Additionally if the number 4 is color blue, the number 2 needs to be color blue and if the number 6 is blue, the number 3 needs to be blue.

So, the number of ways in which we can create a factorfic number is determined by the following cases:

  • The number 2 is blue and the number 3 is blue: In this case we have 1 option for number 1, one for number 2 and 1 for number 3. Taking into account that the number 2 and 3 are blue, if the number 4 and 6 are blue or red doesn't change the fact that the coloring is going to be factorific. So, we have two options for number 3 and 2 options for number 6. Finally the color of the number 5 is independent of the colors of number 2 and 3, so we also have 2 options for coloring number 5 and the coloring is going to be factorific. Then the number of ways for this situation is calculate as:

<u>   1           </u>*<u>        1          </u>*  <u>   1           </u> * <u>          2   </u>  *<u>         2    </u>* <u>    2          </u>=   8

number 1    number 2    number 3   number 4  number 5  number 6

At the same way we can calculate the following cases:

  • The number 2 is blue and the number 3 is red:  If the number 3 is red, the coloring is only going to be factorific is number 6 is red. Then the number of ways for this situation is calculate as:

<u>   1           </u>*<u>        1          </u>*  <u>   1           </u> * <u>          2   </u>  *<u>         2    </u>* <u>    1          </u>=  4

number 1    number 2    number 3   number 4  number 5  number 6

  • The number 2 is red and the number 3 is red:  If the number 2 and 3  are red, the coloring is only going to be factorific is number 4 and 6 are red. Then the number of ways for this situation is calculate as:

<u>   1           </u>*<u>        1          </u>*  <u>   1           </u> * <u>           1   </u>  *<u>         2    </u>* <u>    1          </u>=  2

number 1    number 2    number 3   number 4  number 5  number 6

  • The number 2 is red and the number 3 is blue:  If the number 2 is red, the coloring is only going to be factorific is number 4 is red. Then the number of ways for this situation is calculate as:

<u>   1           </u>*<u>        1          </u>*  <u>   1           </u> * <u>          1   </u>  *<u>         2    </u>* <u>    2          </u>=  4

number 1    number 2    number 3   number 4  number 5  number 6

If we sum all the cases, we obtain 18 ways to make a factorific coloring. So the probability can be calculated as:

P= \frac{18}{64} =  0.28125

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