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iogann1982 [59]
3 years ago
11

What is true about angle ∠APD?

Mathematics
1 answer:
Stolb23 [73]3 years ago
4 0

Answer:

HEY MATE FIRST OF ALL THE QUESTION  IS NOT COMPLETE. TRY MAKING IT MORE CLEAR NEXT TIME !

Step-by-step explanation:

IF THE QUESTION IS THIS IN THE BELOW THEN HERE IS THE ANSWER  .

What is true about angle ∠APD?

It is to angle Angle A P C.

It is to angle Angle C P B.

SOLUTION :

Answer: It is supplementary to angle Angle A P C.

It is vertical to angle Angle C P B.

 I hope this help :)

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Find cos x and cos y! Please help me out! You don’t need to answer all just what you can :)
tangare [24]

Answer:

7. cos(X) = 3/5 = 0.6

cos(Y) = 4/5 = 0.8

8. cos(X) = 15/17 ≈ 0.8824

cos(Y) = 8/17 ≈ 0.4706

9. cos(X) = 1/2 = 0.5

cos(Y) = (√3)/2 ≈ 0.8660

Step-by-step explanation:

The trigonometric ratio for cosine is given as follows;

Cos(\theta) = \dfrac{Adjacent\, side \, to\,  angle}{Hypothenus\, side \, length \ of\, the \  triangle}

7. The adjacent leg length to ∠X = 27

The length of the hypotenuse side of the triangle = 45

∴ cos(X) = 27/45 = 3/5 = 0.6

Cos(X) = 3/5 = 0.6

The adjacent leg length to ∠Y = 36

∴ cos(Y) = 36/45 = 4/5 = 0.8

cos(Y) = 4/5 = 0.8

8. The adjacent leg length to ∠X = 15

The length of the hypotenuse side of the triangle = 17

∴ cos(X) = 15/17 ≈ 0.8824

The adjacent leg length to ∠Y = 8

∴ cos(Y) = 8/17 ≈ 0.4706

9. The adjacent leg length to ∠X = 13

The length of the hypotenuse side of the triangle = 26

∴ cos(X) = 13/26 = 1/2 = 0.5

Cos(X) = 1/2 = 0.5

The adjacent leg length to ∠Y = 13·√3

∴ cos(Y) = 13·√3/26 = (√3)/2 ≈ 0.8660

cos(Y) = (√3)/2 ≈ 0.8660.

4 0
3 years ago
A tree with a height of 4 ft casts a shadow 15ft long on the ground how tall is another tree that cast a shadow which is 20ft lo
wariber [46]

Height of another tree that cast a shadow which is 20ft long is 5 feet approximately

<h3><u>Solution:</u></h3>

Given that tree with a height of 4 ft casts a shadow 15ft long on the ground

Another tree that cast a shadow which is 20ft long

<em><u>To find: height of another tree</u></em>

We can solve this by setting up a ratio comparing the height of the tree to the height of the another tree and shadow of the tree to the shadow of the another tree

\frac{\text {height of tree}}{\text {length of shadow}}

Let us assume,

Height of tree = H_t = 4 feet

Length of shadow of tree = L_t = 15 feet

Height of another tree = H_a

Length of shadow of another tree = L_a = 20 feet

Set up a proportion comparing the height of each object to the length of the shadow,

\frac{\text {height of tree}}{\text {length of shadow of tree}}=\frac{\text { height of another tree }}{\text { length of shadow of another tree }}

\frac{H_{t}}{L_{t}}=\frac{H_{a}}{L_{a}}

Substituting the values we get,

\frac{4}{15} = \frac{H_a}{20}\\\\H_a = \frac{4}{15} \times 20\\\\H_a = 5.33

So the height of another tree is 5 feet approximately

8 0
3 years ago
After moving 5 units up, 3 units right, and 4 units down, the ending position is (9, 6). What was the starting position.
Anika [276]
You reverse what you did, so first you go 5 units down which makes the coordinates (9,1) then you move 3 units left which then is (6,1). Then you go 4 units up which lets you end out at (6,5). 
6 0
3 years ago
MARK AS BRAINLIEST
labwork [276]

Answer:

C [-2 < x]

Step-by-step explanation:

-6(x - 2) < 24

________ ___

-6 -6

x - 2 > -4

+ 2 + 2

_________

x > -2

** Whenever you divide\multiply by a negative, you reverse the inequality symbol.

I am joyous to assist you anytime.

6 0
3 years ago
If x = 6, then what is y in this equation
svet-max [94.6K]

Answer:

y equals 4 because if you substitute solve and isolate you get that answer.

5 0
3 years ago
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