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TiliK225 [7]
2 years ago
14

HELP CANT FIND ANYWHERE ON THE SITE IF RIGHT ANSWER U GET CLOUT AND BRAIN

Mathematics
2 answers:
Maksim231197 [3]2 years ago
5 0

Answer:

B

Step-by-step explanation:

Fynjy0 [20]2 years ago
3 0
The answer is B step by step:
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7.13 In the original study of regression toward the mean, Sir Francis Galton noted a tendency for offspring of both tall and sho
Lena [83]

Answer: All heights could be the same based on probability

Step-by-step explanation:

7 0
3 years ago
Shane buys fishing line in rolls of 700 yards of line per roll. How many feet of fishing line are in one roll?
Vesna [10]
The answer is 2,100. since there are 3 feet in 1 yard, you would multiple 700 by 3.
3 0
3 years ago
Point G(−7, 4) is translated using the rule (x+10, y−6). What is the x-coordinate of G′ ?
den301095 [7]

Answer:

x = 3

Step-by-step explanation:

The translation rule (x + 10, y - 6) means add 10 to the original x- coordinate and subtract 6 from the original y- coordinate, that is

G(- 7, 4) → G'(- 7 + 10, 4 - 6) → G'(3, - 2)

6 0
3 years ago
Does a statistics course improve a student's mathematics skills,as measured by a national test? Suppose a random sample of 13 st
viva [34]

Answer:

There is not enough evidence to support the claim that the scores after the stats course are significantly higher than the scores before (the difference in the scores is higher than 0).

P-value=0.042.

Step-by-step explanation:

The question is incomplete:

The data of the scores for each student is:

Before    After

430        465

485        475

520        535

360        410

440        425

500        505

425        450

470        480

515        520

430        430

450        460

495        500

540        530

We will generate a sample for the difference of scores (before - after) and test that sample.

The sample of the difference is [35 -10 15 50 -15 5 25 10 5 0 10 5 -10]

This sample, of size n=13, has a mean of 9.615 and a standard deviation of 18.423.

The claim is that the scores after the stats course are significantly higher than the scores before (the difference in the scores is higher than 0).

Then, the null and alternative hypothesis are:

H_0: \mu=0\\\\H_a:\mu> 0

The significance level is 0.01.

The estimated standard error of the mean is computed using the formula:

s_M=\dfrac{s}{\sqrt{n}}=\dfrac{18.423}{\sqrt{13}}=5.11

Then, we can calculate the t-statistic as:

t=\dfrac{M-\mu}{s/\sqrt{n}}=\dfrac{9.615-0}{5.11}=\dfrac{9.615}{5.11}=1.882

The degrees of freedom for this sample size are:

df=n-1=13-1=12

This test is a right-tailed test, with 12 degrees of freedom and t=1.882, so the P-value for this test is calculated as (using a t-table):

P-value=P(t>1.882)=0.042

As the P-value (0.042) is bigger than the significance level (0.01), the effect is  not significant.

The null hypothesis failed to be rejected.

There is not enough evidence to support the claim that the scores after the stats course are significantly higher than the scores before (the difference in the scores is higher than 0).

4 0
2 years ago
Observe the equation below, can a value be found for x to make the equation true? Why or why not? 0=4x
Fiesta28 [93]
You have written 0 = 4x.

The value of x that makes it true is x = 0, given that 4 times 0 is 0.

Nevertheless, I think you wanted to write 0 = 4 ^x (this is 4 raised to the power 4).

In that case, there is not any valued of x that satisfies the equation. This is, the equation is always false.

That is because, there is not any value of x for which 4^x is zero. The range of this function is al the positive values of x, which exclude zero.
3 0
3 years ago
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