Answer:
Step-by-step explanation:
The length of the base is the distance between the points 4+2i and 10+4i, so
The middle point of the base is placed at point
The length of the height is the distance between the points 5+9i and 7+3i
So, the area of the triangle is
Answer:
where −5 ≤ x ≤ 3
Step-by-step explanation:
The given function is .
We want to select the option that describes all the solutions to the parabola.
The domain of the parabola is −5 ≤ x ≤ 3.
This means that any x=a on −5 ≤ x ≤ 3 that satisfies (a,f(a)), is a solution.
This can be rewritten as
Therefore for x belonging to −5 ≤ x ≤ 3, all solutions are given by:
where −5 ≤ x ≤ 3.
A quadratic equation is in the form of ax²+bx+c. The time at which the height of the ball is 16 feets is 0.717 seconds and 1.221 seconds.
<h3>What is a quadratic equation?</h3>A quadratic equation is an equation whose leading coefficient is of second degree also the equation has only one unknown while it has 3 unknown numbers. It is written in the form of ax²+bx+c.
The complete question is:
A ball is thrown from an initial height of 2 feet with an initial upward velocity of 31 ft/s. The ball's height h (in feet) after 7 seconds is given by the following, h=2+31t-16t². Find all values of t for which the ball's height is 16 feet. Round your answer(s) to the nearest hundredth.
The time at which the height of the ball is 16 feet can be found by,
h = 2 + 31t - 16t²
16 = 2 + 31t - 16t²
16 - 2 - 31t + 16t² = 0
16t² - 31t + 14 = 0
t = 0.717 , 1.221
Hence, the time at which the height of the ball is 16 feets is 0.717 seconds and 1.221 seconds.
Learn more about Quadratic Equations:
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