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3 years ago

800 divided by 10 to the power 3

Mathematics

1 answer:

Blababa [14]3 years ago

7 0

I think that the answer you are looking for is 0.3

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If you knew that the vertical intercept for a straight line was 15, that the slope was -.5, and that the independent variable ha

Finger [1]

Y=-.5x+15 plug in 8 for x and you get 11

7 0

3 years ago

Find two numbers that multiply to -72 and add up to -1

Andrews [41]

Answer:

-8 and 9

Step-by-step explanation:

-8 x 9 = -72

and -8 + 9 = 1

7 0

3 years ago

"Trigonometric Models" (50 POINTS)<br> Is my graph right?

ch4aika [34]

Answer:

Yes, this graph is absolutely right for the function y = $2\sin(2x)-3$ .

Step-by-step explanation:

firstly we will calculate amplitude, period, phase shift, and vertical shift.

Use the standard form $a\sin(bx-c)+d$ to calculate the values of amplitude, period, phase shift, vertical shift.

here a = 2

b = 2

c = 0

d = -3

Amplitude = |a| = 2

period = $\frac{2\pi}{|b|}$

= $\frac{2\pi}{2}$ = $\pi$

phase shift = $\frac{c}{b}$ = 0

and vertical shift = d = -3

so, by using this information, if we plot the graph then the graph obtained will be same as the given graph.

6 0

3 years ago

On Sunday, chara ran 6 more miles than he did on Saturday. If he ran m miles on Saturday, which expression represents how many m

sattari [20]

Answer:

Is A supposed to be 6 x m or no??

Step-by-step explanation:

8 0

3 years ago

Solve the equation on the interval [0,2π]

WARRIOR [948]

$\bf 16sin^5(x)+2sin(x)=12sin^3(x)
\\\\\\
16sin^5(x)+2sin(x)-12sin^3(x)=0
\\\\\\
\stackrel{common~factor}{2sin(x)}[8sin^4(x)+1-6sin^2(x)]=0\\\\
-------------------------------\\\\
2sin(x)=0\implies sin(x)=0\implies \measuredangle x=sin^{-1}(0)\implies \measuredangle x=
\begin{cases}
0\\
\pi \\
2\pi 
\end{cases}\\\\
-------------------------------$

$\bf 8sin^4(x)+1-6sin^2(x)=0\implies 8sin^4(x)-6sin^2(x)+1=0$

now, this is a quadratic equation, but the roots do not come out as integers, however it does have them, the discriminant, b² - 4ac, is positive, so it has 2 roots, so we'll plug it in the quadratic formula,

$\bf 8sin^4(x)-6sin^2(x)+1=0\implies 8[~[sin(x)]^2~]^2-6[sin(x)]^2+1=0
\\\\\\
~~~~~~~~~~~~\textit{quadratic formula}
\\\\
\begin{array}{lcccl}
& 8 sin^4& -6 sin^2(x)& +1\\
&\uparrow &\uparrow &\uparrow \\
&a&b&c
\end{array} 
\qquad \qquad 
sin(x)= \cfrac{ - b \pm \sqrt { b^2 -4 a c}}{2 a}
\\\\\\
sin(x)=\cfrac{-(-6)\pm\sqrt{(-6)^2-4(8)(1)}}{2(8)}\implies sin(x)=\cfrac{6\pm\sqrt{4}}{16}
\\\\\\
sin(x)=\cfrac{6\pm 2}{16}\implies sin(x)=
\begin{cases}
\frac{1}{2}\\\\
\frac{1}{4}
\end{cases}$

$\bf \measuredangle x=
\begin{cases}
sin^{-1}\left( \frac{1}{2} \right)
sin^{-1}\left( \frac{1}{4} \right)
\end{cases}\implies \measuredangle x=
\begin{cases}
\frac{\pi }{6}~,~\frac{5\pi }{6}\\
----------\\
\approx~0.252680~radians\\
\qquad or\\
\approx~14.47751~de grees\\
----------\\
\pi -0.252680\\
\approx 2.88891~radians\\
\qquad or\\
180-14.47751\\
\approx 165.52249~de grees
\end{cases}$

3 0

3 years ago