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AnnZ [28]
3 years ago
9

800 divided by 10 to the power 3

Mathematics
1 answer:
Blababa [14]3 years ago
7 0
I think that the answer you are looking for is 0.3

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If you knew that the vertical intercept for a straight line was 15, that the slope was -.5, and that the independent variable ha
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Y=-.5x+15 plug in 8 for x and you get 11
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Find two numbers that multiply to -72 and add up to -1​
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-8 and 9

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-8 x 9  = -72

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"Trigonometric Models" (50 POINTS)<br> Is my graph right?
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Answer:

Yes, this graph is absolutely right for the function y = 2\sin(2x)-3.

Step-by-step explanation:

firstly we will calculate amplitude, period, phase shift, and vertical shift.

Use the standard form a\sin(bx-c)+d to calculate the values of amplitude, period, phase shift, vertical shift.

here a = 2

     b = 2

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Amplitude = |a|  = 2

period = \frac{2\pi}{|b|}

           = \frac{2\pi}{2} = \pi

phase shift = \frac{c}{b} = 0

and vertical shift = d = -3

so, by using this information, if we plot the graph then the graph obtained will be same as the given graph.

6 0
3 years ago
On Sunday, chara ran 6 more miles than he did on Saturday. If he ran m miles on Saturday, which expression represents how many m
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Answer:

Is A supposed to be 6 x m or no??

Step-by-step explanation:

8 0
3 years ago
Solve the equation on the interval [0,2π]
WARRIOR [948]
\bf 16sin^5(x)+2sin(x)=12sin^3(x)&#10;\\\\\\&#10;16sin^5(x)+2sin(x)-12sin^3(x)=0&#10;\\\\\\&#10;\stackrel{common~factor}{2sin(x)}[8sin^4(x)+1-6sin^2(x)]=0\\\\&#10;-------------------------------\\\\&#10;2sin(x)=0\implies sin(x)=0\implies \measuredangle x=sin^{-1}(0)\implies \measuredangle x=&#10;\begin{cases}&#10;0\\&#10;\pi \\&#10;2\pi &#10;\end{cases}\\\\&#10;-------------------------------

\bf 8sin^4(x)+1-6sin^2(x)=0\implies 8sin^4(x)-6sin^2(x)+1=0

now, this is a quadratic equation, but the roots do not come out as integers, however it does have them, the discriminant, b² - 4ac, is positive, so it has 2 roots, so we'll plug it in the quadratic formula,

\bf 8sin^4(x)-6sin^2(x)+1=0\implies 8[~[sin(x)]^2~]^2-6[sin(x)]^2+1=0&#10;\\\\\\&#10;~~~~~~~~~~~~\textit{quadratic formula}&#10;\\\\&#10;\begin{array}{lcccl}&#10;& 8 sin^4& -6 sin^2(x)& +1\\&#10;&\uparrow &\uparrow &\uparrow \\&#10;&a&b&c&#10;\end{array} &#10;\qquad \qquad &#10;sin(x)= \cfrac{ -  b \pm \sqrt {  b^2 -4 a c}}{2 a}&#10;\\\\\\&#10;sin(x)=\cfrac{-(-6)\pm\sqrt{(-6)^2-4(8)(1)}}{2(8)}\implies sin(x)=\cfrac{6\pm\sqrt{4}}{16}&#10;\\\\\\&#10;sin(x)=\cfrac{6\pm 2}{16}\implies sin(x)=&#10;\begin{cases}&#10;\frac{1}{2}\\\\&#10;\frac{1}{4}&#10;\end{cases}

\bf \measuredangle x=&#10;\begin{cases}&#10;sin^{-1}\left( \frac{1}{2} \right)&#10;sin^{-1}\left( \frac{1}{4} \right)&#10;\end{cases}\implies \measuredangle x=&#10;\begin{cases}&#10;\frac{\pi }{6}~,~\frac{5\pi }{6}\\&#10;----------\\&#10;\approx~0.252680~radians\\&#10;\qquad or\\&#10;\approx~14.47751~de grees\\&#10;----------\\&#10;\pi -0.252680\\&#10;\approx 2.88891~radians\\&#10;\qquad or\\&#10;180-14.47751\\&#10;\approx 165.52249~de grees&#10;\end{cases}
3 0
3 years ago
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