Solve 3,200 divided by 10 using a area model

PLEASE HELP! NEED TO SUBMIT ASAP!!!!!!!! PLEASE, THANK YOU IN ADVANCE!!!!! 11PTS

Leni [432]

This is a table with 6 lines.
In each line, the number in the first column is the 'x' value.

All you have to do on each line is ...

--- substitute the 'x' value in (100 + 23x), simplify it,
and write the result in the middle column

then

--- substitute the 'x' number in 90(1.2ˣ) , simplify it,
and write the result in the last column.

On the first line, x=0.

100 + 23x = 100 + 0 = 100. Write 100 in the middle column.

90(1.2ˣ) = 90(1) = 90. Write 90 in the last column.

Then go on to the second line, where x=1.

You'll make it.

7 0

3 years ago

Consider this equation.

AnnyKZ [126]

Answer:

I know u saw me before but the answer is B hope it helps! =)

7 0

3 years ago

If UV ≅ UX and WX=23, what is VW? VW =

expeople1 [14]

Answer: VW= 23

Step-by-step explanation:

Because UV = UX the bisector has to split it evenly therefor WX = VW

So the answer is 23! Does this make sense?

7 0

2 years ago

Find the x intercept and y intercept for 6x-2y=18 . provide an explanation and show steps

allochka39001 [22]

Answer:

The slope intercept form would be y = 3x - 9

Step-by-step explanation:

To find this slone in slope intercept form, all we need to do is solve for y.

6x - 2y = 18 ---> Subtract 6x from both sides

-2y = -6x + 18 ----> Divide both sides by -2

y = 3x - 9

3 0

4 years ago

A financial advisor is analyzing a family's estate plan. The amount of money that the family has invested in different real esta

Pachacha [2.7K]

Answer:

The amount of money separating the lowest 80% of the amount invested from the highest 20% in a sampling distribution of 10 of the family's real estate holdings is $238,281.57.

Step-by-step explanation:

Let the random variable X represent the amount of money that the family has invested in different real estate properties.

The random variable X follows a Normal distribution with parameters μ = $225,000 and σ = $50,000.

It is provided that the family has invested in n = 10 different real estate properties.

Then the mean and standard deviation of amount of money that the family has invested in these 10 different real estate properties is:

$\mu_{\bar x}=\mu=\$225,000\\\\\sigma_{\bar x}=\frac{\sigma}{\sqrt{n}}=\frac{50000}{\sqrt{10}}=15811.39$

Now the lowest 80% of the amount invested can be represented as follows:

$P(\bar X$

The value of z is 0.84.

*Use a z-table.

Compute the value of the mean amount invested as follows:

$\bar x=\mu_{\bar x}+z\cdot \sigma_{\bar x}$

$=225000+(0.84\times 15811.39)\\\\=225000+13281.5676\\\\=238281.5676\\\\\approx 238281.57$

Thus, the amount of money separating the lowest 80% of the amount invested from the highest 20% in a sampling distribution of 10 of the family's real estate holdings is $238,281.57.

6 0

3 years ago