Based on the distance of the pitcher's mound from the home plate, the path of the ball, and the height the ball was hit, the distance the outfielder threw the ball is C. 183.0 ft.
<h3>How far did the outfielder throw the ball?</h3>
Based on the shape of a mound, the law of cosines can be used.
The distance the ball was thrown by the outfielder can therefore be d.
Distance is:
d² = 60.5² + 226² - (2 x 60.5 x 226 x Cos(39))
d ²= 33,484.42ft
Then find the square root:
d = √33,484.42
= 182.9874
= 183 ft
Find out more solving for distance at brainly.com/question/10739348
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ANSWER
1.39
EXPLANATION
The given quadratic equation is
This is the same as,
Comparing to
We have
a=2, b=3,c=-8
Using the quadratic formula, the solution is given by:
We substitute the values to get,
The positive root is
to the nearest hundredth.
Answer:
151,000
Step-by-step explanation:
Sorry no I’m only in 8th :(
Answer:
What was the regular price of the T-shirt?
What question is being asked in this word problem?
- what is the regular cost of the t-shirt purchased by Jill.
What is the regular price of the skirt?
How much money does Jill have left?
- without considering sales tax, Jill has $90 - $31 = $59 left.
- If I use the sales tax from where I live, the sales tax = $1.86, so the money that Jill will have left = $59 - $1.86 = $57.14
How much does the T-shirt normally cost?
What is the amount Jill pays in sales tax?
- since you do not include the sales tax % in the question, I will simply use the sales tax from where I live = $31 x 6% = $1.86
Step-by-step explanation:
skirt $21
t-shirt = p - $8
before sales tax, total cost was $31
$21 + p - $8 = $31
p = $18
