Hugo is buying DVDs that cost $15 each. He has a coupon for $5 off his

Line segment CD is shown on a coordinate grid:

slavikrds [6]

<span>
A) C'D' and CD are equal in length. Is your answer have a nice day. ;)</span>

6 0

3 years ago

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Please help me!!!!!!!!!!

Alex

The answer is C. 20.3 miles per hour.

In order to solve this, we have to first convert our time into hours. We start with 11 seconds, but need to convert to hours. Since there are 3600 seconds in an hour, we need to divide by that unit rate.

11 seconds/3600 = .00305 hours

Now we need to convert our meters into miles. The problem lets us know that there are 1609 meters in a mile, so we need to divide the 100 meters by 1609.

100 meters/1609 = .0621 miles.

Now to find miles per hour, we divide the miles we got by the hours.

.00305 miles/ .0621 miles = 20.3 miles per hour.

5 0

3 years ago

According to records, the amount of precipitation in a certain city on a November day has a mean of inches, with a standard devi

Mekhanik [1.2K]

Answer:

The probability that the mean daily precipitation will be of X inches or less for a random sample of n November days is the p-value of $Z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}$ , in which $\mu$ is mean amount of inches of rain and $\sigma$ is the standard deviation.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this question:

Mean $\mu$ , standard deviation $\sigma$

n days:

This means that $s = \frac{\sigma}{\sqrt{n}}$

Applying the Central Limit Theorem to the z-score formula.

$Z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}$

What is the probability that the mean daily precipitation will be of X inches or less for a random sample of November days?

The probability that the mean daily precipitation will be of X inches or less for a random sample of n November days is the p-value of $Z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}$ , in which $\mu$ is mean amount of inches of rain and $\sigma$ is the standard deviation.

5 0

2 years ago

2

pav-90 [236]

Answer:

I think A=66.67?Not too sure,sorry if I am wrong

Step-by-step explanation:

3 0

2 years ago

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Free points just put he is the best

drek231 [11]