Answer:
m=2 and n=3
Step-by-step explanation:
<u>Step</u> :-
Given ![[ 2 x^{n}y^{2} ]^m = 4 x^6 y^4](https://tex.z-dn.net/?f=%5B%202%20x%5E%7Bn%7Dy%5E%7B2%7D%20%5D%5Em%20%3D%204%20x%5E6%20y%5E4)
using algebraic formula 
now

now equating 'x' powers, we get

....(1)
now

Equating 'y' powers ,we get
2 m=4
m=2
substitute m= 2 in equation (1)
we get
2 n=6
n=3
verification:-
substitute m=2 and n=3 , we get
![[ 2 x^{n}y^{2} ]^m = 4 x^6 y^4](https://tex.z-dn.net/?f=%5B%202%20x%5E%7Bn%7Dy%5E%7B2%7D%20%5D%5Em%20%3D%204%20x%5E6%20y%5E4)


both are equating so m= 2 and n=3
Answer:
823516
Step-by-step explanation:
hope this helps
Answer:
D. Minimum at (3, 7)
Step-by-step explanation:
We can add and subtract the square of half the x-coefficient:
y = x^2 -6x +(-6/2)^2 +16 -(-6/2)^2
y = (x -3)^2 +7 . . . . . simplify to vertex form
Comparing this to the vertex for for vertex (h, k) ...
y = (x -h)^2 +k
We find the vertex to be ...
(3, 7) . . . . vertex
The coefficient of x^2 is positive (+1), so the parabola opens upward and the vertex is a minimum.
False.
Multiplying two negatives gives a positive.
Answer:
c. -17
Step-by-step explanation:
We have the function f(x) = -2t^2 + 1 and we need to solve for x if f(-3).
Substitute the x in the function with the x in the equation :
f(-3) = -2(-3)^2 + 1
Solve for the answer :
f(-3) = -2(9) + 1
f(-3) = -18 + 1
f(-3) = -17
Therefore, c. -17 is the answer.