The person has 1 5/6 cake left because 3 2/4 - 1 2/3 = 1 5/6! Hope this helps ^0^
Explanation
Rewriting Expression in different parts.
= 3 + 2/4 + 1 + 2/3.
Solving The Whole Number Parts.
3 + 1 = 4
Solving The Fraction Parts.
2/4 + 2/3 = ?
Find the LCD of 2/3 and 2/4 and Rewrite to solve with equivalent Fractions.
LCD = 12
6/12 + 8/12 = 14/12
Simplify the Fraction Part.
14/12 = 7/6
Simplify The Fraction Part Again.
7/6 = 1 1/6
Combining The Whole Numbers With The Fractions.
4 + 1 + 1/6 = 5 1/6
Hope this helps ^0^! ;D
Answer:
Option b is the correct answer
Step-by-step explanation:
The graph in the picture is the graph of a quadratic equation and it takes the shape of a parabola.
The points on the x axis through which the parabola cuts across is used to determine the solution of the quadratic equation.
Looking at the parabola formed from the plotted points, it cuts the x axis at
x = -1 and x= -2
These are the factors of the equation. To get the equation, we multiply the factors.
x= -1, x +1 = 0
x =-2 , x + 2= 0
The equation is (x+1)(x+2)
Expanding the brackets,
x×x + x×2 +1×x + 1×2
= x^2 + 2x + x +2
= x^2 + 3x +2 = 0
Option b is the correct answer
Hey there
<span>Quadrilateral "four sided shape"</span>
A Quadrilateral has four-sides and<span> it is </span>2-dimensional shape
Squares and quadrilaterals have
4 sides
4 vertices
Hope this helps
Answer:
H = 20.5 hours
I = 19.5 Hours
Step-by-step explanation:
Start by creating a system.
I = time which the inlet pipe takes alone to fill the pond
H = time which the hose takes alone to fill the pond
10/I + 10/H = 10
H - I = 1
H = 20.5 hours
I = 19.5 Hours
Answer:
Place the decimal before the last digit in both number i.e. 1602.3 and 65.4
Step-by-step explanation:
We are given the numerical expression 16023÷654.
Here, we have,
Dividend = 16023
Divisor = 654
it is required that the quotient of the division to be between 23 and 25.
If we take the numbers,
1602.3 and 65.4
This gives us,
.
Hence, placing the decimal before the last digit in both number will give the desired result.
