Answer:
answer in the attached image
Step-by-step explanation:
hope this helps, have a nice day :)
Answer:
C
Step-by-step explanation:
-2x^2 + 2x -3
-2(5)^2=
-50
2(5)
= 10
-50+10-3
is -43 so C
Answer:
Yes
Step-by-step explanation:
Answer:
B) x scale of -15 to 15
C) y scale of 0 to 15
Step-by-step explanation:
The change in y-value is 1/4 of the change in x-value, and the y-intercept is 8. That means a y-scale of -30 to 30 would not be well-utilized over a small range of x. (It would take an x-range of about 200 to make much use of that y-scale.)
An appropriate y-scale is one that has 8 near its middle. The corresponding x-scale is then roughly ±4 times half the y-scale. The closest choices are ...
-15 ≤ x ≤ 15 . . . . choice B
0 ≤ y ≤ 15 . . . . . . choice C
Answer:
C = 97.20
Step-by-step explanation:
Given that C varies as r² then the equation relating them is
C = kr² ← k is the constant of variation
To find k use the condition C = 202.80 when r = 2.6
k = = = 30
C = 30r² ← equation of variation
When r = 1.8, then
C = 30 × 1.8² = 97.20