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Crazy boy [7]
3 years ago
7

Consider the two expressions 4b(b+1) and (2b+7)(2b-8). Compare their values if b=-3, b=-2, and if b=10. Is it true that for an v

alue of b the value of the first expression is greater than the value of the second expression
Mathematics
1 answer:
noname [10]3 years ago
8 0

Answer:

If b=-3 then the first expression is equal to 24 and the second expression is equal to -14.

If b=-2 then the first expression is equal to 8 and the second expression is equal to -36.

If b=10 then the first expression is equal to 440 and the second expression is equal to 324.

Yes, it is true.

Step-by-step explanation:

b=-3:

4b(b+1)=4(-3)(-3+1)=-12(-2)=24

(2b+7)(2b-8)=(2(-3)+7)(2(-3)-8)=(-6+7)(-6-8)=1(-14)=-14

b=-2:

4b(b+1)=4(-2)(-2+1)=-8(-1)=8

(2b+7)(2b-8)=(2(-2)+7)(2(-2)-8)=(-4+7)(-4-8)=3(-12)=-36

b=10:

4b(b+1)=4(10)(10+1)=40(11)=440

(2b+7)(2b-8)=(2(10)+7)(2(10)-8)=(20+7)(20-8)=27(12)=324

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NNADVOKAT [17]

1.) 9(4) + 8(5)

36 + 40 = 74

2.) 2(3) + 8(3)

6 + 24 = 30

3.) 4(5) + 7(5)

20 + 35 = 55

4.) 10(4) + 18(5)

40 + 90 = 130

5.) 2 + 8(1/4)

2 + 2 = 4

6.) 9(1/3) + 8(1/4)

3 + 2 = 5

7.) 3(8) + 7(4)

24 + 28 = 52

8.) 12(1/4) + 16(5)

4 + 80 = 84

8 0
3 years ago
I WILL MARK BRAINIEST <br> PLEASE ANSWER QUESTION 26
Oksana_A [137]

Answer: (0,-10) and the transformation should be a reflection

Step-by-step explanation:

5 0
3 years ago
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A mountain climber ascends 800 feet per hour from his original position. After 6 hours, his final position is 11,600 feet above
coldgirl [10]
<span>To find the beginning position, we need to know how many feet the climber has ascended in the 6-hour time frame. At the rate of 800 feet per hour, this would total to 4,800 feet in 6 hours (800 * 6). Subtracting this amount from the final position would give the elevation at the beginning of the ascent: (11600 - 4800) = 6,800 feet above sea level to begin.</span>
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4 years ago
You previously found the mean of this data set. Use that in answering the question. 63, 89, 92, 73, 79, 72, 34, 36, 94, 21, 25,
kicyunya [14]

Answer:

Sum of squares of differences = 11239.74

Step-by-step explanation:

We are given the following data set:

63, 89, 92, 73, 79, 72, 34, 36, 94, 21, 25, 93, 22, 90, 79

We have to calculate the sum of square of the data set.

Formula:

\text{Sum of square of differences} = \sum (x_i -\bar{x})^2

where x_i are data points, \bar{x} is the mean and n is the number of observations.  

Mean = \displaystyle\frac{\text{Sum of all observations}}{\text{Total number of observation}}

Mean =\displaystyle\frac{962}{15} = 64.13

Sum of squares of differences =

1.284444444 + 618.3511113 + 776.5511113 + 78.61777778 + 221.0177779 + 61.88444445 + 908.0177776 + 791.4844443 + 892.017778 + 1860.484444 + 1531.417778 + 833.2844446 + 1775.217777 + 669.0844446 + 221.0177779

= 11239.74

3 0
3 years ago
Part A
olasank [31]
<h3>Answer:</h3>
  • B. f(x) = 3,000(0.85)^x
  • $1566.02
<h3>Step-by-step explanation:</h3>

Part A

At the end of the year, the value of the computer system is ...

... (beginning value) - 15% · (beginning value) = (beginning value) · (1 - 0.15)

... = 0.85 · (beginning value)

Since the same is true for the next year and the next, the multiplier after x years will be 0.85^x. Then the value after x years is ...

... f(x) = (beginning value) · 0.85^x

The beginning value is given as $3000, so this is ...

... f(x) = 3000·0.85^x

____

Part B

For x=4, this is ...

... f(4) = 3000·0.85^4 = 3000·0.52200625 ≈ 1566.02

The value after 4 years is $1566.02.

8 0
3 years ago
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