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3 years ago

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How to solve inequalities

1 answer:

sertanlavr [38]3 years ago

4 0

Add or subtract numbers from both sides

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Suppose the number 1155 is written as the product of three positive integers. What is the smallest possible value of the sum of

ozzi

3. the equation I used is: 3×5×77

6 0

3 years ago

Two random samples are taken, with each group asked if they support a particular candidate. A summary of the sample sizes and pr

Minchanka [31]

Answer:

And we got $\alpha/2 =0.01$ so then the value for $\alpha=0.02$ and then the confidence level is given by: $Conf=1-0.02=0.98[/tex[ or 98%Step-by-step explanation:A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval". The margin of error is the range of values below and above the sample statistic in a confidence interval. Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean". [tex]p_1$ represent the real population proportion for 1

$\hat p_1 =0.768$ represent the estimated proportion for 1

$n_1=92$ is the sample size required for 1

$p_2$ represent the real population proportion for 2

$\hat p_2 =0.646$ represent the estimated proportion for 2

$n_2=95$ is the sample size required for 2

$z$ represent the critical value for the margin of error

The population proportion have the following distribution

$p \sim N(p,\sqrt{\frac{p(1-p)}{n}})$

The confidence interval for the difference of two proportions would be given by this formula

$(\hat p_1 -\hat p_2) \pm z_{\alpha/2} \sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1} +\frac{\hat p_2 (1-\hat p_2)}{n_2}}$

For this case we have the confidence interval given by: (-0.0313,0.2753). From this we can find the margin of erro on this way:

$ME= \frac{0.2753-(-0.0313)}{2}=0.1533$

And we know that the margin of erro is given by:

$ME=z_{\alpha/2} \sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1} +\frac{\hat p_2 (1-\hat p_2)}{n_2}}$

We have all the values except the value for $z_{\alpha/2}$

So we can find it like this:

$0.1533=z_{\alpha/2} \sqrt{\frac{0.768(1-0.768)}{92} +\frac{0.646 (1-0.646)}{95}}$

And solving for $z_{\alpha/2}$ we got:

$z_{\alpha/2}=2.326$

And we can find the value for $\alpha/2$ with the following excel code:

"=1-NORM.DIST(2.326,0,1,TRUE)"

And we got $\alpha/2 =0.01$ so then the value for $\alpha=0.02$ and then the confidence level is given by: $Conf=1-0.02=0.98$ or 98%

7 0

3 years ago

A certain city's population is 120,000 and decreases 1.4% per year for 15 years.

mart [117]

Answer:

Decay Problem.

Decay rate, r = 0.014
Initial Amount =120,000

$P(t)=120000(0.986)^t$
P(10)=104,220

Step-by-step explanation:

The exponential function for growth/decay is given as:

$P(t)=P_0(1 \pm r)^t, where:\\P_0$ is the Initial Population\\r is the growth/decay rate\\t is time$

In this problem:

The city's initial population is 120,000 and it decreases by 1.4% per year.

Since the population decreases, it is a Decay Problem.

Decay rate, r=1.4% =0.014
Initial Amount =120,000

Therefore, the function is:

$P(t)=120000(1 - 0.014)^t\\P(t)=120000(0.986)^t$

When t=10 years

$P(10)=120000(0.986)^10\\=104219.8\\\approx 104220 $ (to the nearest whole number)$

8 0

3 years ago

Complete the ratio- I WILL GIVE BRAINLIEST TO WHOEVER ANSWERS FIRST!<br><br> 8:44=1::?

miskamm [114]

Answer:

8 /8 =1

44/8=5,5

so the ratio is 1:5,5

3 0

2 years ago

A polygon is reflected across a line. The angles in the original figure are compared to the corresponding angles in the image to

irina [24]

None. <span>They will always be congruent.</span>

5 0

3 years ago

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