The average rate of change of f(x) on the interval [5, 5 + h] is 1
<h3>How to find the
average rate of change of f(x) on the interval [5, 5 + h]?</h3>
The equation of the function is given as:
f(x) = x + 11
The interval is given as: [5, 5 + h]
So, we start by calculating f(5) and f(5 + h)
This gives
f(5) = 5 + 11 = 16
f(5 + h) = 5 + h + 11 = h + 16
The average rate of change of f(x) on the interval [5, 5 + h] is then calculated as:
Rate = [f(5 + h) - f(5)]/[5 + h - 5]
Substitute the known values in the above equation
Rate = (h + 16 - 16)/(5 + h - 5)
Evaluate the sum and the difference
Rate = h/h
This gives
Rate = 1
Hence, the average rate of change of f(x) on the interval [5, 5 + h] is 1
Read more about the average rate of change at
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==> I noticed that to draw a B or a D, you have to use both straight and curved lines. Maybe that's the pattern.
Hold up, hee haw, whoa ! There are no curved lines, only straight ones, in F and H. That can't be the pattern.
==> I noticed that to go from B to D in the alphabet, you skip one letter (C). Maybe that's the pattern.
Well Hyola ! If you skip one letter in the alphabet each time, you can get from D to F, and then from F to H, and then from H to J .
I'm willing to go out on a limb, bet 3¢ , and state my conjecture that the pattern is "To get from one term to the next term, skip one letter in the alphabet.".
I can't be absolutely positive and say "That's definitely it !". There may be other patterns that can produce the same 5 letters but then not work after that. But the pattern of "Skip-one" can produce these 5 letters, so it's a reasonable conjecture.
Answer:
JL=3x
Step-by-step explanation:
JL=5x+2
-2. -2
JL=3x
90. This is because a whole term is 360 degrees. So divide it by 4 to get the answer of a quarter term. Same goes for half term, dived 360 by 2 to get 180 degrees.