The third one, 2 to the power of 5 over 6
√2 * 3√2
convert from radical form to exponent form to solve for the same root
( x^m/n = n√x^m )
2^(1/2) * 2^(1/3)
2^{3/6} * 2^{2/6} - find common denominator (6)
6√(2^3) * 6√(2^2) - convert back to radical form
6√(2^3 * 2^2)- combine
6<span>√(</span>2^5)
then convert to exponential form again
~ 2^5/6 ~
Answer:
The answer would be c
Step-by-step explanation:
I did it edge yesterday
Answer:
Step-by-step explanation:
2 functions start by making a domain
Function 1: -3≤x<1
Function 2: -1≤x≤1
Now come up with equations
Function 1= x+3
Function 2= 5
Now put it all together
f(x)= x+3 for -3≤x<1 and 5 for -1≤x≤1
81 + 70 + x = 3(73)
first multiply 3(73)
81 + 70 + x = 219
combine like terms
151 + x = 219
subtract 151 from both sides
x = 68
Joaquin needs to score a 68 on her next test to maintain an average of 73.
Given: p=2, h=8
5p^2=h
5(2)^2=8 ------- substitution here
5(4)=8
20 doesn't equal 8
I did exponents first because it comes before multiplication in the order of opertions.
