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zloy xaker [14]
2 years ago
7

Roman Knoze is considering two investments. Each will cost $20,000 initially. Project 1 will return annual cash flows of $10,000

in each of three years. Project 2 will return $5,000 in year 1, $10,000 in year 2, and $15,000 in year 3. Roman requires a minimum rate of return of 10%. What is the net present value of Project 2
Business
1 answer:
Artyom0805 [142]2 years ago
6 0

Answer:

NPV= $4,079.63

Explanation:

Giving the following information:

Initial cost= -$20,000

Rate of return= 10%

<u>To calculate the net present value, we need to use the following formula:</u>

NPV= -Io + ∑[Cf/(1+i)^n]

<u>First, we need to discount the cash flows:</u>

PV= Cfn / (1+i)^n

Cf1= 5,000/1.1= 4,545.45

Cf2= 10,000/1.1^2= 8,264.46

Cf3= 15,000/1.1^3= 11,269.72

Total PV= $24,079.63

Now, the NPV:

NPV= -20,000 + 24,079.63

NPV= $4,079.63

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3 years ago
Which of the following is a correct formula when markup is based on selling price
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<span>perhaps u want the formula for the percentage of markup, giving the cost and selling price.
..(selling price) = (cost) + (Markup)
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5 0
3 years ago
The Alpha Division of the Carlson Company manufactures product X at a variable cost of $40 per unit. Alpha Division's fixed cost
zheka24 [161]

Answer:

$70 per unit.

Explanation:

Based on the information given we were been told that the market price of X costs the amount of $70 per unit which simply means that market price exists, based on this the transfer price of X in a situation were each division is been treated as a profit making center will be the market price of $70 per unit.

8 0
3 years ago
Agan Interior Design provides home and office decorating assistance to its customers. In normal operation, an average of 2.5 cus
Phantasy [73]

Answer:

A) Single-server single-phase model (M/M/1).

\lambda=2.5 \,customers/hour\\\\\mu=6\,customers/hour

B) The goal is not met, as the average time waiting for service is 5.56 minutes.

C) The new mean service rate is 7.5 customers/hour.

In this case, the average time waiting for service is 4 minutes, so the goal is met.

Explanation:

A) This situation can be modeled as a single-server single-phase model (M/M/1).

The mean arrival rate is 2.5 customers per hour.

\lambda=2.5 \,customer/h

The mean service rate is 6 customers per hour, calculated as:

\mu=\frac{60\, min/h}{10 \,min/customer}=6\, customer/h

B) The average waiting time for a customer can be expressed as:

W_q=\frac{\lambda}{\mu}\frac{1}{\mu-\lambda}  =\frac{2.5}{6}\frac{1}{6-2.5} =0.417*0.222=0.093\,hours\\\\W_q=0.093\,hours*(60min/h)=5.56 \,min

The average waiting time is 5.56 minutes, so it is more than the goal of 5 minutes.

C) If the average time spent per customer to 8 minutes, the mean service rate becomes

\mu=\frac{60\, min/h}{8 \,min/customer}=7.5\, customer/h

An the average waiting time for the service now becomes:

W_q=\frac{\lambda}{\mu}\frac{1}{\mu-\lambda}  =\frac{2.5}{7.5}\frac{1}{7.5-2.5} =0.333*0.2=0.067\,hours\\\\W_q=0.067\,hours*(60min/h)=4 \,min

The average time is now 4 minutes, so the goal is achieved.

6 0
3 years ago
Sheffield Corporation incurred the following costs in 2020. Cost of laboratory research aimed at discovery of new knowledge $145
Stells [14]

Answer: Debit Research and Development expense $477,000

Credit Cash $477,000

Explanation:

The journal entry simply refers to the recording of transactions that a company makes and it should be noted that the total amount that's gotten in the debit column must be equal to the total amount that us gotten in the credit column.

Based on the information given in the question, the journal entry for Sheffield Corporation will be:

Debit Research and Development expense $477,000

Credit Cash $477,000

8 0
2 years ago
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