1 answer:
Answer:
Step-by-step explanation:
This form is already factored so it can help us to find the intercepts with the x-axis
how ?
- The intercepts with the x-axis are simply the points where f(x)=0
from the factored form we can deduce that x=2 and x=3 are the points that represent the intercepts with the x-axis since f(2)=0 and f(3)=0
- The intercept with the y-axis is the image of 0 so f(0)=(0-2)(0-3)=6
so :
- The intercepts with the x-axis are (2,0) and (3,0)
- The intercept with they-axis is (0,6)
To get the standard form we should develop :
= x²-5x+6
now the vertex form with the axis of symmetry :
- There are many ways to do it but here is the simplest one :
the standard form is x²-5x+6 :
The coordinates of the vertex are : (
,f(
) )
- let A be the vertex : a(
,
) - the axis of simmetry is x= 5/2
- The vertex form is : 1*(x-
)²/(1/4)
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5=7
Step-by-step explanation:
(5x³ + 4x²) - (6x² - 2x - 9)
-1(6x²) -1(-2x) -1(-9) = -6x² + 2x + 9
5x³ + 4x² - 6x² + 2x + 9
5x³ - 2x² + 2x + 9 Choice D.
The answer is 55 and 25 (25)x2=50, 50+5=(55), 55+25=80.