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3 years ago

What’s the solution of x+4<8

Mathematics

2 answers:

aniked [119]3 years ago

7 0

Answer:

x<4

Move all terms not containing x to the right side of the inequality.

snow_tiger [21]3 years ago

6 0

Answer:

x<4 Correct use the photomather

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Mr Edwards buys 2 new knobs for each of his kitchen cabinets. How many knobs does he buy?

Andreas93 [3]

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Step-by-step explanation:

You need to find out how many cabinets it is

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2 years ago

A bowl contained 250 skittles. The result of 25 fruit-flavored candies pulled at random is given below. Based on this informatio

Anastaziya [24]

OK so you have 250 skittles. But you only pull out 25. You pull out 5 red skittles, 7 yellow skittles,8 orange skittles,2 green skittles and 3 purple skittles. So how many red skittles are in the whole box. The way i would look at it is theres 5 red skittles in every 25 skittles. So whats 250 divided by 25 that would be 10. So you can imagine you have 10 groups of skittles. In each group theres 5 skittles. So all together there would be 50 red skittles. Sooo based on the infromation there would be 50 red skittles expected in the box. I hope this helped pls mark me as brainliest!!

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2 years ago

Which classification best represents a triangle with side lengths 6 cm, 10 cm, and 12 cm?

DedPeter [7]

Answer:

obtuse because 62 + 102 < 122

3 0

2 years ago

Read 2 more answers

What is a correct way to rewrite p m p n pmpn ?

Akimi4 [234]

Answer:

$p^{4}$ $m^{2}$ $n^{2}$

Step-by-step explanation:

collect like terms and multiply

(p×p×p×p)×(m×m)×(n×n)

5 0

3 years ago

Read 2 more answers

Form a polynomial function whose real zeros are in -1, 1, 3 and whose degree is 3

polet [3.4K]

The polynomial function whose real zeros are in -1, 1, 3 and whose degree is 3 is $x^3-3x^2-x+3=0$

Step-by-step explanation:

We need to find a polynomial function whose real zeros are in -1, 1, 3 and whose degree is 3.

If -1, 1 and 3 are real zeros, it can be written as:

x= -1, x= 1, and x = 3

or x+1=0, x-1=0 and x-3=0

Finding polynomial by multiply these factors:

$(x+1)(x-1)(x-3)=0\\(x+1)(x(x-3)-1(x-3))=0\\(x+1)(x^2-3x-x+3)=0\\(x+1)(x^2-4x+3)=0\\x(x^2-4x+3)+1(x^2-4x+3)=0\\x^3-4x^2+3x+x^2-4x+3=0\\Combining\,\,like\,\,terms:\\x^3-4x^2+x^2+3x-4x+3=0\\x^3-3x^2-x+3=0$

So, The polynomial function whose real zeros are in -1, 1, 3 and whose degree is 3 is $x^3-3x^2-x+3=0$

Keywords: Real zeros of Polynomials

Learn more about Real zeros of Polynomials at:

#learnwithBrainly

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3 years ago