For the answer to the question above,
<span>a) Use F = k * q1 * q2 / d²
where k = 8.99e9 N·m²/C²
and q1 = -1.602e-19 C (electron)
and q2 = 1.602e-19 C (proton)
and d = distance between point charges = 0.53e-10 m
The negative result indicates "attraction".
b) Here, just use F = ma
where F was found above, and
m = mass of electron = 9.11e-31kg, if memory serves
a = radial acceleration
c) Now use a = v² / r
where a was found above
and r was given
d) period T = 2π / ω = 2πr / v
where v was found above
and r was given </span>
Answer:
52º, 128º
Step-by-step explanation:
8. Because ∠6 is an opposite angle to ∠5, ∠6=∠5=52º;
9. Because line a//line b, ∠6=∠4=52º, so ∠7=180º–52º=128º
Answer:
yes i could help you
Step-by-step explanation:
<em>For</em><em> </em><em>the</em><em> </em><em>attached</em><em> </em><em>image</em><em>,</em><em> </em><em>note</em><em> </em><em>that</em><em> </em><em>slope</em><em> </em><em>is</em><em> </em><em>the</em><em> </em><em>same</em><em> </em><em>thing</em><em> </em><em>as</em><em> </em><em>gradient</em><em>.</em>
1) y = 2x + 4
2) Substituting in x = 1 and y = 1,
1 = 4(1) + c
1 = 4 + c
c = -3
So, the equation is y = 4x - 3
Answer: Option A

Step-by-step explanation:
In the graph we have a piecewise function composed of a parabola and a line.
The parabola has the vertex in the point (0, 2) and cuts the y-axis in y = 2.
The equation of this parabola is
Then we have an equation line
Note that the interval in which the parabola is defined is from -∞ to x = 1. Note that the parabola does not include the point x = 1 because it is marked with an empty circle " о ."
(this is
)
Then the equation of the line goes from x = 1 to ∞ . In this case, the line includes x = 1 because the point at the end of the line is represented by a full circle
.
(this is
)
Then the function is:
