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kogti [31]
3 years ago
12

A student dissolves 1 gram of sugar in 10 grams of water. She then

Chemistry
1 answer:
mixas84 [53]3 years ago
7 0

Answer:

11 grams

Explanation:

your welcome!!!!!

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An essential utensil for various tasks from cleaning vegatables to training pasta ir tin contents​
zavuch27 [327]

Correct question: A tool used for vegetable strainer,it is essential for various tasks from cleaning vegetables to straining pasta or tin contents.

Answer: The tool is called COLANDER.

Explanation:

In the kitchen, there are different types of equipments and utensils which makes work easier and faster. Examples of such equipment/ utensils includes:

--> graters,

--> cutleries ( spoon, fork, knife)

--> colanders

--> Pots

--> Blenders

These utensils are made up of rubber, plastics, wood, ceramics and stainless steel.

A Colander is an important kitchen utensil, a type of strainer with perforated holes. The holes allows fluid to drain leaving behind the solid part. It is usually bowl - shaped. It helps in performing the following roles in the kitchen:

--> cleaning vegetables

--> straining of pasta

--> straining of tin contents

Colanders are usually made of stainless steel, plastics and ceramics.

4 0
3 years ago
URGENT!! This is timed, PLEASE HELP!
Andrews [41]

Answer:

99.24 gm of nitrogen .

Explanation:

molecular weight of ammonia = 17 , molecular weight of nitrogen = 28.

2 NH₃(g) + 3 CuO(s) → 1N₂(g) + 3 Cu(s) + 3 H₂O(g)

2 x 17 gm                      28 gm

( 34 gm )

34 gm of ammonia forms 28 gms of nitrogen

1 gm of ammonia   forms 28 / 34 gms of nitrogen

120.51 gn of ammonia forms 28 x 120.51 / 34 gms of nitrogen

28 x 120.51 / 34 gms

= 99.24 gms of nitrogen will be formed .

8 0
4 years ago
Name two methods scientists use to obtain empirical evidence
adell [148]
Through hypothesis and experiments
4 0
4 years ago
Draw and name the structures of the carboxylic acids and esters you put together using molecular models.
Neporo4naja [7]

Answer:

This question is incomplete

Explanation:

However, when the carboxylic acids and esters put together are obtained, the procedure below can be followed in drawing and naming them.

For carboxylic acid,

1) it should be noted that the functional group here is -COOH which is drawn as -C = OH

      |

     OH

2) The carbon of the functional group is included among the carbon to be counted when naming the structure. For example, the compound below is propanoic acid.

CH₃CH₂COOH - As you can see that there are 3 carbons linked chain there.

3) As can be seen in (2) above, the suffix "oic" is used to name carboxylic acids

4) The carbon chain here is saturated (meaning there is no double or triple bond within the carbon chain)

Example of a structure of carboxylic acid is

H₃C - CH₂ - CH₂ - C = OH

                              |

                             OH

The structure above is a butanoic acid

For ester

1)The functional group here is -COO- . which can be drawn as

- C = O

   |

  O -

(meaning one oxygen atom is double bonded to the carbon and the other oxygen atom is bonded to another carbon chain)

2) The alkyl group attached to the oxygen atom is first of all mentioned before the carbon chain attached from the left is mentioned. For example, CH₃CH₂CH₂COOCH₂CH₃ is ethyl butanoate

3) As seen from (2) above, the suffix "oate" is used to end the name of esters

4) As also seen from (2) above, the carbon of the functional group is also included while counting the carbon chain of the parent name (butanoate).

5) The carbon chains here are also saturated.

Example of this ester is

CH₃CH₂C = O

              |

             O - CH₂CH₃

The name of this compound is ethyl propanoate

3 0
3 years ago
Balance the following chemical equations. Questions 6-10
aleksandr82 [10.1K]
6. Put a 2 before H2O, and a 4 before HF 
7. Just put a 2 before HCI
8. I can't seem to figure this one out...sorry. I can keep trying if you want tho...
9. Put a 2 before HNO3 and a 3 in front of O2 
10. I think you just put a 2 in front of H2O.
I tried my best. I hope I got at least one right...I started this stuff yesterday..good luck 
4 0
3 years ago
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