Energy were released from the walnut, q = 1,673.6 J
<h3>Equation :</h3>
To find the energy using formula,
q = mcΔt
where,
q is charge
m is mass
c is specific heat of water
Δt is change in temperature
So, given
t₁ = 50°C
t₂ = 60°C
m = 40g
c = 4.184 J/g
Now putting the values known,
We get,
q = mc(t₂ - t₁)
q = 40g x 4.184 J/g x (60 - 50)
q = 167.36 J x 10
q = 1,673.6 J
<h3>What is heat energy?</h3>
Heat is the thermal energy that is transferred when two systems with different surface temperatures come into contact. Heat is denoted by the letters q or Q and is measured in Joules.
To know more about specific heat :
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Answer:
2H⁺(aq) + 2OH⁻(aq) --> 2H2O(l)
Explanation:
2HBr(aq)+Ba(OH)2(aq)⟶2H2O(l)+BaBr2(aq)
We break the compounds into ions. Only compounds in the aqueous form can be turned into ions.
The ionic equation is given as;
2H⁺(aq) + 2Br⁻(aq) + Ba²⁺(aq) + 2OH⁻(aq) --> 2H2O(l) + Ba²⁺(aq) + 2Br⁻(aq)
Upon eliminating the spectator ions; The net equation is given as;
2H⁺(aq) + 2OH⁻(aq) --> 2H2O(l)
A scientific theory is a well tested explanation of a natural phenomenon.
Answer:
10
Explanation:
Given endpoints:
E (-2,2) and F(4, -6)
To find the distance between two points;
Use the expression below;
D =
x₁ = -2,
x₂ = 4
y₁ = 2
y₂ = -6
Insert the parameters and solve;
D = 
D =
= 10
Answer:
The energy of attraction between the cation and anion is 1.231 X 10⁻¹¹ J
Explanation:
Let the charge on the cation be q₁
Also let the charge on the anion be q₂
A cation q₁ with a valence of 1, has a charge of 1 X 1.602×10⁻¹⁹C = 1.602×10⁻¹⁹C
An anion q₂ with a valence of 3, has a charge of 3 X 1.602×10⁻¹⁹C = 4.806 ×10⁻¹⁹C
The distance between the two charges is 7.5nm = 7.5 X10⁻⁹m
Energy of attraction = 
Where k is coulomb's constant = 8.99 X 10⁹ Nm₂/C₂
Energy of attraction = 
Energy of attraction = 1.231 X 10⁻¹¹ J
Therefore, the energy of attraction between the cation and anion is 1.231 X 10⁻¹¹ J