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mrs_skeptik [129]
3 years ago
15

how many milliliters of a stock solution of 2.00M KNO3 would you need to prepare 100.0mL of 0.150M KNO3?

Chemistry
1 answer:
larisa86 [58]3 years ago
3 0
The answer is 7.5 ml
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What does the reaction rate say about a reaction?
miss Akunina [59]

Answer:

It shows the change in concentration of a reactant or product per unit of time, expressed as mol/(L · s)

Explanation:

The reaction rate is the speed at which a chemical reaction proceeds.

So if the reaction rate is the speed at which a chemical reaction happens/occurs, then the reaction rate will tell us about the concertation of the chemicals. It shows the change in concentration of a reactant or product per unit of time, expressed as mol/(L · s)

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3 years ago
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3 years ago
Which laws can be combined to form the ideal gas law?
Morgarella [4.7K]
Answer: Charles's law, Avogadro's law and Boyle's law.

Justification:

Boyle's law states that at constant temperature  PV = constant

Charles law states that at constant pressure V/T = constant

Avogadro's law states that at constant pressure ant temperature, equal volume of gases contain equal number of moles: V/n = constant

Ideal gas law states PV/nT = constant => PV = nT*constant = PV = nTR
7 0
4 years ago
If I had 3.50 x 10 24molecules of Cl2 gas, how many grams is this?
Zinaida [17]

Answer:

412 g Cl₂

General Formulas and Concepts:

<u>Atomic Structure</u>

  • Reading a Periodic Table
  • Moles
  • Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

<u>Stoichiometry</u>

  • Using Dimensional Analysis

Explanation:

<u>Step 1: Define</u>

[Given] 3.50 × 10²⁴ molecules Cl₂

[Solve] grams Cl₂

<u>Step 2: Identify Conversions</u>

Avogadro's Number

[PT] Molar Mass of Cl - 35.45 g/mol

Molar Mass of Cl₂ - 2(35.45) = 70.9 g/mol

<u>Step 3: Convert</u>

  1. [DA] Set up:                                                                                                       \displaystyle 3.50 \cdot 10^{24} \ molecules \ Cl_2(\frac{1 \ mol \ Cl_2}{6.022 \cdot 10^{23} \ molecules \ Cl_2})(\frac{70.9 \ g \ Cl_2}{1 \ mol \ Cl_2})
  2. [DA] Divide/Multiply [Cancel out units]:                                                           \displaystyle 412.072 \ g \ Cl_2

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 3 sig figs.</em>

412.072 g Cl₂ ≈ 412 g Cl₂

5 0
3 years ago
Which is the empirical formula for a compound that contains 64.75g nitrogen and 185.25 oxygen
Svetach [21]

Answer:

What is the formula for a compound that contains 64.75 g nitrogen and 185.25 g oxygen? D. N2O5

The name of a hydrate is calcium chloride dihydrate. What is its formula? B. CaCl2 x 2H20

Explanation:

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5 0
3 years ago
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