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olya-2409 [2.1K]
3 years ago
10

Find the local maximum and minimum values of f(x)=x^3-6x^2+5

Mathematics
1 answer:
Roman55 [17]3 years ago
5 0

Answer:

Local maxima at x=0

Local minima at x=4

Step-by-step explanation:

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2 years ago
A/ab-bsquare + b/ab-asquare?​
lord [1]

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Step-by-step explanation:

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\dfrac{a}{ab-b^2}+\dfrac{b}{ab-a^2}=\dfrac{a}{b(a-b)}+\dfrac{b}{a(b-a)}\\\\=\dfrac{a}{b(a-b)}+\dfrac{b}{-a(-b+a)}\\\\=\dfrac{1}{a-b}(\dfrac{a}{b}-\dfrac{b}{a})\\\\=\dfrac{a^2-b^2}{ab(a-b)}\\\\=\dfrac{(a-b)(a+b)}{ab(a-b)}\\\\=\dfrac{(a+b)}{ab}

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7 0
3 years ago
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