I would say B.
Hope this helped!
:)
Answer:
im not sure im really sorry
Step-by-step explanation:
im answering this because i have the same question
Hello from MrBillDoesMath!
Answer:
x = 2 and 10
Discussion:
Approach 1:
20 = (-10)*(-2) and (-10) + (-2) = -12 the coefficients of the polynomial. Hence
x^2 -12x + 20 = ( x- 2) * ( x-10)
Approach 2:
From the quadratic formula ( a = 1, b = -12, c = 20)
x = ( -(-12) +\- sqrt( ((-12)^2 - 4*1*20) ) / (2 * 1)
= ( 12 +\- sqrt( 144-80) ) /2
= (12 +\- sqrt(64) ) /2
= (12 +\- 8 ) /2
x = ( 12 + 8) /2 = 20/2 = 10
or
x = ( 12 - 8)/ 2 = 4/2 = 2
Thank you,
MrB
Answer:
1. Let's solve for x.
−3x+5y=−6
Step 1: Add -5y to both sides.
−3x + 5y + −5y = −6 + −5y
−3x = −5y − 6
Step 2: Divide both sides by -3.
−3x
−3
=
−5y−6
−3
x=
5
3
y+2
2. Let's solve for x.
6x−10y=12
Step 1: Add 10y to both sides.
6x−10y+10y=12+10y
6x=10y+12
Step 2: Divide both sides by 6.
6x
6
=
10y+12
6
x=
5
3
y+2
