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nordsb [41]
3 years ago
8

This problem is substitution. X^-2-9X^-1+18=0

Mathematics
1 answer:
loris [4]3 years ago
6 0
Can explain it better?
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(+7) x (-3) math intergers
IrinaK [193]

Answer:

-21

Step-by-step explanation:

- * + = -

- * - = +

+ * + = +

Here + * - = -

7* 3 = 21 and sign is -ve

4 0
2 years ago
Read 2 more answers
Austin keeps a right conical basin for the birds in his garden as represented in the diagram. The basin is 40 centimeters deep,
Lina20 [59]

The shortest distance between the tip of the cone and its rim exits 51.11cm.

<h3>What is the shortest distance between the tip of the cone and its rim?​</h3>

If you draw a line along the middle of the cone, you'd finish up with two right triangles and the line even bisects the angle between the sloping sides. The shortest distance between the tip of the cone and its rim exists in the hypotenuse of a right triangle with one angle calculating 38.5°. So, utilizing trigonometry and allowing x as the measurement of the shortest distance between the tip of the cone and its rim.

Cos 38.5 = 40 / x

Solving the value of x, we get

Multiply both sides by x

$\cos \left(38.5^{\circ}\right) x=\frac{40}{x} x

$\cos \left(38.5^{\circ}\right) x=40

Divide both sides by $\cos \left(38.5^{\circ}\right)$

$\frac{\cos \left(38.5^{\circ}\right) x}{\cos \left(38.5^{\circ}\right)}=\frac{40}{\cos \left(38.5^{\circ}\right)}

simplifying the above equation, we get

$x=\frac{40}{\cos \left(38.5^{\circ}\right)}

x = 51.11cm

The shortest distance between the tip of the cone and its rim exits 51.11cm.

To learn more about right triangles refer to:

brainly.com/question/12111621

#SPJ9

7 0
1 year ago
Read 2 more answers
1.Show that the statement p: “If x is a real number such that x3 + 4x = 0, then x is 0” is true by
Genrish500 [490]

If x is a real number such that x3 + 4x = 0 then x is 0”.Let q: x is a real number such that x3 + 4x = 0 r: x is 0.i To show that statement p is true we assume that q is true and then show that r is true.Therefore let statement q be true.∴ x2 + 4x = 0 x x2 + 4 = 0⇒ x = 0 or x2+ 4 = 0However since x is real it is 0.Thus statement r is true.Therefore the given statement is true.ii To show statement p to be true by contradiction we assume that p is not true.Let x be a real number such that x3 + 4x = 0 and let x is not 0.Therefore x3 + 4x = 0 x x2+ 4 = 0 x = 0 or x2 + 4 = 0 x = 0 orx2 = – 4However x is real. Therefore x = 0 which is a contradiction since we have assumed that x is not 0.Thus the given statement p is true.iii To prove statement p to be true by contrapositive method we assume that r is false and prove that q must be false.Here r is false implies that it is required to consider the negation of statement r.This obtains the following statement.∼r: x is not 0.It can be seen that x2 + 4 will always be positive.x ≠ 0 implies that the product of any positive real number with x is not zero.Let us consider the product of x with x2 + 4.∴ x x2 + 4 ≠ 0⇒ x3 + 4x ≠ 0This shows that statement q is not true.Thus it has been proved that∼r ⇒∼qTherefore the given statement p is true.

8 0
2 years ago
B + 12 = 16; 2, 3, 4
Molodets [167]

Answer:

4

Step-by-step explanation:

b+12 =16

-12. -12

b = 4

hope this helps

5 0
3 years ago
Divide 800ml into ratio 3:7
Brums [2.3K]
Simply take the numerator (3) and denominator (7) and add them together. 

3+7 = 10, which means that the ratio will provide parts that are in multiples of 10 depending on the total

so take 10x = 800 

x = 80.

Then multiply this by the numerator and denominator 

3*80/7*80 = 240/560. 
6 0
3 years ago
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