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abruzzese [7]
2 years ago
12

Nowwwwwww pleasssssssss

Computers and Technology
1 answer:
Feliz [49]2 years ago
6 0

the technique used is Data Validation

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Calculate the wait time and turnaround time for FCFS, shortest remaining time, and round-robin by drawing a diagram or chart. As
lidiya [134]

Answer:

id id d

Explanation:

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If a small monster collector has 20 small monster containment devices; intends to use all of those devices; has access to non-un
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The collector can capture nine different types of combinations of monster types.

<u>Explanation</u>:

  • There are twenty small monster containment devices. The collector has access only to non-unique types. They are water, fire and grass types of small monsters.
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Let T be the statement: The sum of any two rational numbers is rational. Then T is true, but the following "proof is incorrect.
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Answer:

the mistake is in the first statement.

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Now lets us put the statement into consideration:

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Which type of network medium is used by an integrated services digital network adapter?
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C program for the sales department of a small company. The department has 4 sales person and is selling 5 products. The program
igomit [66]

Answer:

See Explaination

Explanation:

#include<iostream>

using namespace std;

//function to enter sales

void Enter_sale(int sales[5][4])

{

//variables

int product,person,sale_amount;

cout<<"1. Product 1 \n2. Product 2 \n3. Product 3 \n4. Product 4 \n5. Product 5 \n";

//prompt for product

cout<<"Enter Product: ";

cin>>product;

cout<<"1. Sales Person 1 \n2. Sales Person 2 \n3. Sales Person 3 \n4. Sales Person 4 \n";

//prompt for sales

cout<<"Enter Sales Person: ";

cin>>person;

//prompt for sales amount

cout<<"Enter Sales Amount: ";

cin>>sale_amount;

//adding to previous total sales amount

sales[product-1][person-1]=sales[product-1][person-1]+sale_amount;

}

//function to check sales by a person

void Check_salesperson(int sales[5][4])

{

int person,total=0;

cout<<"1. Sales Person 1 \n2. Sales Person 2 \n3. Sales Person 3 \n4. Sales Person 4 \n";

//prompt for person

cout<<"Enter Sales Person: ";

cin>>person;

if(person>=1 && person<=4)

{

//printing details of sales by a person

cout<<"Details of Sales \n";

for(int i=0;i<5;i++)

{

cout<<"Product "<<i+1<<": "<<sales[i][person-1]<<"\n";

total=total+sales[i][person-1];

}

//printing total sales by a person

cout<<"Total: "<<total<<"\n";

}

else

{

cout<<"Error!\n";

}

}

//function to check sales by a product

void Check_product(int sales[5][4])

{

int product,total=0;

cout<<"1. Product 1 \n2. Product 2 \n3. Product 3 \n4. Product 4 \n5. Product 5 \n";

//prompt for product

cout<<"Enter Product: ";

cin>>product;

if(product>=1 && product<=5)

{

//printing details of sales on a product

cout<<"Details of Sales \n";

for(int i=0;i<4;i++)

{

cout<<"Sales Person "<<i+1<<": "<<sales[product-1][i]<<"\n";

total=total+sales[product-1][i];

}

//printing total sales on a product

cout<<"Total: "<<total<<"\n";

}

else

{

cout<<"Error!\n";

}

}

int main()

{

int choice;

int sales[5][4] = {{0,0,0,0},{0,0,0,0},{0,0,0,0},{0,0,0,0},{0,0,0,0}};

while(true)

{

//Menu

cout<<"1. Enter Sales\n2. Check Sales by a Person\n3. Check Sales on a Product\n4. Exit\n";

//choice

cin>>choice;

switch(choice)

{

//if enter sales

case 1:

Enter_sale(sales);

break;

//if check sales by a person

case 2:

Check_salesperson(sales);

break;

//if check sales on a product

case 3:

Check_product(sales);

break;

//if exit

case 4:

exit(0);

//if wrong choice

default:

cout<<"Error!\n";

break;

}

}

}

5 0
3 years ago
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