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Burka [1]
3 years ago
7

Driving is expensive. Write a program with a car's miles/gallon and gas dollars/gallon (both doubles) as input, and output the g

as cost for 20 miles, 75 miles, and 500 miles. Output each floating-point value with two digits after the decimal point, which can be achieved as follows: System.out.printf("%.2f", yourValue); The output ends with a newline.
Computers and Technology
2 answers:
Tatiana [17]3 years ago
4 0

Answer:

const double gasDollarPerGallon = 20 ;

float calCost( double milesPerGallon ) {

   double costPerGallon = milesPerGallon / gasDollarPerGallon;

   System.out.printf ("%.2f/n", &costPerGallon);

int main ( ) {

   scanf ("%2f", &gasDollarPerGallon) ;

   calCost( 20 );

   calCost( 75 );

   calCost( 500 );

Explanation:

The C source code above gets the user input of the gas dollar per gallon from the command prompt and divides the miles per gallon variable in the function call to get the cost of gas for the range of miles. It is also print out as a double with two places.

kiruha [24]3 years ago
4 0

Answer:

def driving_cost(driven_miles, miles_per_gallon, dollars_per_gallon):

  gallon_used = driven_miles / miles_per_gallon

  cost = gallon_used * dollars_per_gallon  

  return cost  

miles_per_gallon = float(input(""))

dollars_per_gallon = float(input(""))

cost1 = driving_cost(10, miles_per_gallon, dollars_per_gallon)

cost2 = driving_cost(50, miles_per_gallon, dollars_per_gallon)

cost3 = driving_cost(400, miles_per_gallon, dollars_per_gallon)

print("%.2f" % cost1)

print("%.2f" % cost2)

print("%.2f" % cost3)

Explanation:

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Answer:

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3 years ago
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Aleks04 [339]

Answer:

// The program below checks if an array is sorted or not

// Program is written in C++ Programming Language.

// Comments are used for explanatory purpose

//Program Starts here

#include<iostream>

using namespace std;

//Function to check if the array is sorted starts here

int isSorted(int arr[], int count)

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// Check if arrays has one or no elements

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return 1;

}

else

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// Check first two elements

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int check = 0;

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}

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}

// Main Method starts here

int main()

{

int count;

cin<<count;

int arr[count];

for(int I = 1; I<=count; I++)

{

cin>>arr[I-1];

}

int n = sizeof(arr) / sizeof(arr[0]);

if (isSorted(arr, n))

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Answer:

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