700,000 + 70,000 + 70
is your answer
hope this helps :D
Answer:
the amount after 5 years using compound continuously is $135.03
Step-by-step explanation:
The computation of the amount after 5 years using compound continuously is as follows
= Principal × e^(rate × time period)
= $110 × e^(4.2% × 5)
= $110 × 1.227525065
= $135.03
Hence, the amount after 5 years using compound continuously is $135.03
We simply applied the above formula so that the correct value could come
And, the same is to be considered
Answer:
- <em>To solve these first swap x and y, solve for y and name it inverse function</em>
3. <u>y = -8x + 2</u>
- x = -8y + 2
- 8y = -x + 2
- y = -x/8 + 2/8
- y = -(18)x + 1/4
f⁻¹(x) = -(18)x + 1/4
-----------------------------------------
4.<u> y = (2/3)x - 5</u>
- x = (2/3)y - 5
- (2/3)y = x + 5
- y = (3/2)x + (3/2)5
- y = 1.5x + 7.5
f⁻¹(x) = 1.5x + 7.5
-----------------------------------------
5. <u>f(x) = 2x² - 6</u>
- x = 2y² - 6
- 2y² = x + 6
- y² = 1/2x + 3
- y =
![\sqrt{1/2x + 3}](https://tex.z-dn.net/?f=%5Csqrt%7B1%2F2x%20%2B%203%7D)
f⁻¹(x) = ![\sqrt{1/2x + 3}](https://tex.z-dn.net/?f=%5Csqrt%7B1%2F2x%20%2B%203%7D)
-----------------------------------------
6. <u>y = (x - 3)²</u>
- x = (y - 3)²
= y - 3- y = 3 +
![\sqrt{x}](https://tex.z-dn.net/?f=%5Csqrt%7Bx%7D)
f⁻¹(x) = 3 + ![\sqrt{x}](https://tex.z-dn.net/?f=%5Csqrt%7Bx%7D)
Answer:
Pattern: subtract 2 from the input to get the output
When the input is 9, the output is 7
When the input is 13, the output is 11
Step-by-step explanation:
» <u>Application + Solution</u>
To find the pattern, we have to look for common things we notice between the input and output.
- After analyzing, we can surely notice that we subtract two from the input each time to get the output because 3 - 2 = 1, 8 - 2 = 6, 15 - 2 = 13, and 20 - 2 = 18.
Now that we realized the pattern, we subtract 2 from 9 and 13.
The fundamental theorem of algebra states that a polynomial with degree n has at most n solutions. The "at most" depends on the fact that the solutions might not all be real number.
In fact, if you use complex number, then a polynomial with degree n has exactly n roots.
So, in particular, a third-degree polynomial can have at most 3 roots.
In fact, in general, if the polynomial
has solutions
, then you can factor it as
![p(x) = (x-x_1)(x-x_2)\ldots (x-x_n)](https://tex.z-dn.net/?f=p%28x%29%20%3D%20%28x-x_1%29%28x-x_2%29%5Cldots%20%28x-x_n%29)
So, a third-degree polynomial can't have 4 (or more) solutions, because otherwise you could write it as
![p(x)=(x-x_1)(x-x_2)(x-x_3)(x-x_4)](https://tex.z-dn.net/?f=p%28x%29%3D%28x-x_1%29%28x-x_2%29%28x-x_3%29%28x-x_4%29)
But this is a fourth-degree polynomial.