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2 years ago

Please answer see the image below

Mathematics

2 answers:

fredd [130]2 years ago

5 0

Answer:

Step-by-step explanation:

total area = rectangle + semi circle

= (11 x 5) + (1/2 * π * 2.5²)

= 55 + 9.8

= 64.8 sq. units

VashaNatasha [74]2 years ago

5 0

Answer:

64.8² units. Hope it's help you.

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Which of the following is not a solution of 3x=5y-1 a.(3,3) b.(7,4) c.(-1/3,0) d.(-2,-1)

erik [133]

3x = 5y - 1

(3,3)...not a solution
(7,4)...not a solution
(-1/3,0)...is a solution
(-2,-1)...is a solution

8 0

3 years ago

Finished the first one don´t understand these.

Mashutka [201]

Answer:

Let "x" be the number of people who can go to the amusement park.

So we have: 19 + 14x ≤ 180. This inequality basically means that the parking cost plus the cost of the tickets for every person cannot cost more than 180 dollars.

Solving this inequality, we get:

19 + 14x ≤ 180

14x ≤ 161

x ≤ 11.5

Obviously, we know that we can't have "half" a person, so the most people who can come to the amusement park would be 11 people, and the answer would be: x ≤ 11

Hope this helps!

4 0

2 years ago

What value of a makes the following equation true?<br> a−8a=210

Alex

Answer:

a=-30

Step-by-step explanation:

4 0

2 years ago

Find the absolute extrema for f(x,y)=4-x^2-y^4+1/2y^2 over the closed disk D:x^2+y^2 is less than or equal to 1

algol [13]

Find the critical points of $f(x,y)$ :

$\dfrac{\partial f}{\partial x}=-2x=0\implies x=0$

$\dfrac{\partial f}{\partial y}=y-4y^3=y(1-4y^2)=0\implies y=0\text{ or }y=\pm\dfrac12$

All three points lie within $D$ , and $f$ takes on values of

$\begin{cases}f(0,0)=4\\f\left(0,-\frac12\right)=\frac{65}{16}\\f\left(0,\frac12\right)=\frac{65}{16}\end{cases}$

Now check for extrema on the boundary of $D$ . Convert to polar coordinates:

$f(x,y)=f(\cos t,\sin t)=g(t)=4-\cos^2-\sin^4t+\dfrac12\sin^2t=3+\dfrac32\sin^2t-\sin^4t$

Find the critical points of $g(t)$ :

$\dfrac{\mathrm dg}{\mathrm dt}=3\sin t\cos t-4\sin^3t\cos t=\sin t\cos t(3-4\sin^2t)=0$

$\implies\sin t=0\text{ or }\cos t=0\text{ or }\sin t=\pm\dfrac{\sqrt3}2$

$\implies t=n\pi\text{ or }t=\dfrac{(2n+1)\pi}2\text{ or }\pm\dfrac\pi3+2n\pi$

where $n$ is any integer. There are some redundant critical points, so we'll just consider $0\le t< 2\pi$ , which gives

$t=0\text{ or }t=\dfrac\pi3\text{ or }t=\dfrac\pi2\text{ or }t=\pi\text{ or }t=\dfrac{3\pi}2\text{ or }t=\dfrac{5\pi}3$

which gives values of

$\begin{cases}g(0)=3\\g\left(\frac\pi3\right)=\frac{57}{16}\\g\left(\frac\pi2\right)=\frac72\\g(\pi)=3\\g\left(\frac{3\pi}2\right)=\frac72\\g\left(\frac{5\pi}3\right)=\frac{57}{16}\end{cases}$

So altogether, $f(x,y)$ has an absolute maximum of 65/16 at the points (0, -1/2) and (0, 1/2), and an absolute minimum of 3 at (-1, 0).

5 0

3 years ago

I’ll give brainliest if u answer within 30 mins

Alecsey [184]

Answer:

96.7 maybe or 6.75 or 5.67 or even 56.77

Step-by-step explanation:

6 0

2 years ago