1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
valkas [14]
2 years ago
13

Your local movie theater sent out promotional coupons for a $6 admission price to a new action movie that was just released. Wit

hout the coupon, the cost of admission is $10. Two hundred people attended the first screening of the day, and the total box office receipts for that screening were $1500. Choose the answer that best describes this situation.
A. There is no solution to this system of equations. This is an impossible situation.
B. 125 people used the coupon, and 75 paid full price.
C. 100 people used the coupon, and 100 paid full price.
D. 75 people used the coupon, and 125 paid full price
Mathematics
2 answers:
Gre4nikov [31]2 years ago
8 0
D. I hope this helps:)
posledela2 years ago
5 0

Answer:

The real answer is b:)

Step-by-step explanation:

You might be interested in
Let x,y \epsilon R. Use mathmatical induction to prove the identity.
mariarad [96]

Step-by-step explanation:

We will prove by mathematical induction that, for every natural n,  

(x-y)(x^{n}+x^{n-1}y+...+xy^{n-1}+y^{n})=x^{n+1}-y^{n+1}

We will prove our base case (when n=1) to be true:

Base case:

(x-y)(x^{n}+x^{n-1}y+...+xy^{n-1}+y^{n})=(x-y)(x^{1}+y^{1})=x^2-y^2=x^{1+1}-y^{1+1}

Inductive hypothesis:  

Given a natural n,  

x^{n+1}-y^{n+1}=(x-y)(x^{n}+x^{n-1}y+...+xy^{n-1}+y^{n})

Now, we will assume the inductive hypothesis and then use this assumption, involving n, to prove the statement for n + 1.

Inductive step:

Observe that, for y=0 the conclusion is clear. Then we will assume that y\neq 0.

(x-y)(x^{n+1}+x^{n}y+...+xy^{n}+y^{n+1})=(x-y)y(\frac{x^{n+1}}{y}+x^{n}+...+xy^{n-1}+y^{n})=(x-y)y(\frac{x^{n+1}}{y})+(x-y)y(x^{n}+...+xy^{n-1}+y^{n})=(x-y)y(\frac{x^{n+1}}{y})+y(x^{n+1}-y^{n+1})=(x-y)x^{n+1}+y(x^{n+1}-y^{n+1})=x^{n+2}-yx^{n+1}+yx^{n+1}-y^{n+2}=x^{n+2}-y^{n+2}\\

With this we have proved our statement to be true for n+1.    

In conlusion, for every natural n,

(x-y)(x^{n}+x^{n-1}y+...+xy^{n-1}+y^{n})=x^{n+1}-y^{n+1}

8 0
3 years ago
$24,000 for new Honda, 2.75% interest rate for 4 years. What is the monthly payment? ( Explanation needed)
noname [10]
2.75/100=0.0275
= 24000 x ( 1 + 0.0275 ) ^ 4= 26750.91
26750.91 - 24000 = 2750.90
i’m sorry if it’s wrong
7 0
3 years ago
Read 2 more answers
a athlete jumps 4 distances in a long jump challange. witch jump dose not round to 4.7 meters? 4.746?,4.680?,4.647?,4.733?.
olga nikolaevna [1]

Answer:

4.647

Step-by-step explanation:

3 0
2 years ago
Help again please (correct answer only)
laiz [17]
The word is not clear
3 0
3 years ago
Read 2 more answers
Simplify (5^3)^6 leaving your answer in index form
Verizon [17]

( {5}^{3} ) ^{6}  =  {5}^{3 \times 6} =  {5}^{18}

5 0
3 years ago
Read 2 more answers
Other questions:
  • How many different three-digit numbers can be written using digits from the set 5, 6, 7, 8, 9 without any repeating digits?
    12·2 answers
  • The number of hours it takes Jack to drive from Boston to Bangor is inversely proportional to his average driving speed. When he
    13·1 answer
  • Pls help I don’t understand
    13·1 answer
  • If U=(1,2,3,4,5,6,7,8,9) <br><br> A=(1,2,3) is A a subset of U and is U a superset of A.
    13·2 answers
  • A school is organizing a cookout where
    7·1 answer
  • which value for R in the table would most likely indicate an association between the conditional variables? 0.09 0.10 0.13 0.79​
    13·2 answers
  • Estimate the difference of 1.2 − 0.4 = ________ by rounding each number to the nearest whole number.
    5·1 answer
  • From 45 quarts to 8 quarts​
    7·2 answers
  • M measures .<br> ​(a) Find the supplement of M.<br> ​(b) Find the complement of M.
    7·1 answer
  • Is 0.9999 really the same as 1
    8·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!