They are not
It goes from
0/0 1/3 2/5 3/6(or 1/2) which are not the same. This makes them not proportional to one another. (I think)
Let the three numbers be x, y, and z.
If the sum of the three numbers is 3, then x+y+z=3
If subtracting the second number from the sum of the first and third numbers gives 9, then x+z-y=9
If subtracting the third number from the sum of the first and second numbers gives -5, then x+y-z=-5
This forms the system of equations:
[1] x+y+z=3
[2] x-y+z=9
[3] x+y-z=-5
First, to find y, let's take do [1]-[2]:
x+y+z=3
-x+y-z=-9
2y=-6
y=-3
Then, to find z, let's do [1]-[3]:
x+y+z=3
-x+-y+z=5
2z=8
z=4
Now that you have y and z, plug them into [1] to find x:
x+y+z=3
x-3+4=3
x=2
So the three numbers are 2,-3, and 4.
Solution:
<u>Note that:</u>
- Given inequality: 3 < x + 3 < 6
<u>Solving the inequality one by one.</u>
- 3 < x + 3
- => -3 + 3 < x
- => 0 < x
- => x + 3 < 6
- => x < 6 - 3
- => x < 3
The inequality is <u>0 < x < 3.</u>
Answer:
S=D/T
34/15=2.26 mph
Step-by-step explanation: