1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Feliz [49]
3 years ago
13

MERRY CHRISTMAS 100 points SPREAD THE LOVE

Mathematics
2 answers:
nignag [31]3 years ago
7 0
THANK U SO MUCH HAVE A HAPPY HOLIDAY!!
Zielflug [23.3K]3 years ago
5 0

Answer:

Thank you!

Step-by-step explanation:

Did you know that if you gave all the gifts listed in the "Twelve Days of Christmas," it would equal 364 presents!?

A partridge in a pear tree,

Two turtle doves,

Three french hens,

Four calling birds,

Five gold rings,

Six geese a-laying

Seven swans a-swimming,

Eight maids a-milking,

Nine ladies dancing,

Ten lords a-leaping,

Eleven pipers piping,

Twelve drummers drumming.

Happy learning!

You might be interested in
If two pounds of meat will serve 5 people how many pounds will be needed to serve 13 people
miv72 [106K]
The answer is 5.2 pounds of meat. To find this just divide the number of people by what the information you have about servings. 13/5=2.6(number of sets), then you multiply that by how many pounds are in each set. 2.6 sets* 2 pounds per set= 5.2 pounds.
I hope this helped!
4 0
3 years ago
Write the number another way. 9 tens 5 ones
galina1969 [7]
Its 95
 
Tens = 90
Ones = 5

90 + 5 = 95
5 0
3 years ago
Hello good morning!! Anyone watch anime? My favorite is yu yu hakusho or one piece
topjm [15]

Answer:

Good Morning my favorite is Attack on Titan.

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
Find the value using identities (302)3
Arlecino [84]

Answer:

108,000,934

1.08934×10^8

Step-by-step explanation:

(302)^3

(a+b)^3

(a+b)^3==a^3+3a^2b+3ab^2+b^3

(300+2)

(300)^3+3(300^2+2)+3(300+2^2)+2^3

27,000,000+81,000,002+8+924

108,000,002+8+924

108,000,934 or 1.08934×10^8

8 0
3 years ago
5.
ANTONII [103]

The greatest possible number of club members is 7

<em><u>Solution:</u></em>

Given that, local readers’ club has a set of 49 hardback books and a set of 21 paperbacks

Each set can be divided equally among the club members

To find the greatest possible number of club members, we have to find the greatest common factor of 49 and 21

The greatest number that is a factor of two (or more) other numbers.

When we find all the factors of two or more numbers, and some factors are the same ("common"), then the largest of those common factors is the Greatest Common Factor.

<em><u>Greatest common factor of 49 and 21:</u></em>

The factors of 21 are: 1, 3, 7, 21

The factors of 49 are: 1, 7, 49

Then the greatest common factor is 7

Thus, the greatest possible number of club members is 7

7 0
3 years ago
Other questions:
  • Find the equation of the line passing
    5·1 answer
  • A firm that stocks lightbulbs gathers the following information: Demand = 19,500 units per year, Ordering cost = $25 per order,
    15·1 answer
  • Check all of the steps that would be used to solve this equation: 2(x-5)=24
    13·1 answer
  • Raymond spends 1/10 of his vacation budget on a car rental. Write an expression for how much Raymond has to spend on the rest of
    14·2 answers
  • A common inhabitant of human intestines is the bacterium escherichia coli, named after the german pediatrician theodor escherich
    13·1 answer
  • A rectangle has side lenghs X +2 and 3X -1 write an expression that represents the perimeter of the rectangle then simplify the
    13·1 answer
  • A drawer has 4 red shirts and 8 green shirts. What is the ratio of red to yhe total number of shirts
    5·2 answers
  • The volume of a cylinder is 4pix^3 cubic units and its height is x units.
    6·1 answer
  • Emergency please help I have been trying to solve this all day I am stûpid
    9·1 answer
  • Select the correct answer from each drop-down menu.
    13·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!