Let i = sqrt(-1) which is the conventional notation to set up an imaginary number
The idea is to break up the radicand, aka stuff under the square root, to simplify
sqrt(-8) = sqrt(-1*4*2)
sqrt(-8) = sqrt(-1)*sqrt(4)*sqrt(2)
sqrt(-8) = i*2*sqrt(2)
sqrt(-8) = 2i*sqrt(2)
<h3>Answer is choice A</h3>
Answer:
18
Step-by-step explanation:
21-n; n=3
Substitute n for 3:
Solve.
Answer:
x=2.5
Step-by-step explanation:
Solve for x in this systems of equations, we already have two values which equal y so half the work is finished for us.
Starting with the equation:

Add x to both sides to remove the negative x on the right side of the equation:

Subtract 12 from both sides to remove the 12 on the left side of the equation:

Divide both sides by 2 to cancel out the x coefficient
