Q = 4.6E-6 C
<span>E = 2.6 kV/mm = 2600 kV/m = 2600000 V/m </span>
<span>ε = 8.85E-12 F/m </span>
<span>E = Q/Aε </span>
<span>A = Q/Eε = 4.6E-6/(2600000*8.85E-12) = 0.2 m^2</span>
Answer:7.93 m/s
Explanation:
Given
mass of ball
Mass of hanging ball
Length of string
Maximum angle turned
is the initial velocity of ball 1 and 0 is the initial velocity of ball 2
For Perfectly elastic final velocity of ball 1 and 2 is given by
where and are the velocity of 1 and 2 before collision
thus
By energy conservation on second ball we get
Kinetic energy=Potential Energy
thus
Answer:
first class lever
in a first class lever fulcrum is b/w input and output force