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Gre4nikov [31]
3 years ago
8

What voltage can be applied by a resistor190 Ω and 100 A?

Physics
1 answer:
Anettt [7]3 years ago
4 0

Answer:

V=IR

V=100×190

=19000 V

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A 500-W heating coil designed to operate from 110V is made of Nichrome wire 0.500 mm in diameter. (b) What If? Now consider the
melamori03 [73]

The power delivered to the coil is 721.31 Watts

<h3>How to determine the power</h3>

Given that;

  • Power of the heating coil = 500W
  • Voltage = 110V
  • Diameter of the Nichrome wire = 0. 500mm, radius = 0. 500/2 = 0. 00025m

But the formula for power is given a;

Power, P = V²/R

Then , R = V²/P

R = (110)²/ 500 = 24. 2Ω

To determine the length,

Length, L = RA/ ρ

L = 24. 2 × ( 0. 0025)² × 3. 142/ 10^-6

L = 4. 32m

We also have that;

Resistance, R = Ro( 1 + α ΔT)

R = 24. 2 ( 1 + 0. 0004 × 1180)

R = 35. 62Ω

Current, I = V R

Current, I = 110/24.2 = 4. 5 A

Power delivered = I²R =  (4.5)² × 35. 62 = 721.31 Watts

Thus, the power delivered to the coil is 721.31 Watts

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6 0
2 years ago
Two wires A and B with circular cross sections are made of the same metal and have equal lengths, but the resistance of wire A i
AlexFokin [52]

The resistance of wire B will be D. 1/2R

<h3>What is resistance?</h3>

It should be noted that resistance simply means the measure of the opposition to the current flow that's in an electric circuit.

Based on the information given, the resistance will be calculated thus:

= 2L/4A

= 1/2pL/A

= R/2

Therefore, the resistance of wire B will be D. 1/2R

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Two wires A and B with circular cross sections are made of the same metal and have equal lengths, but the resistance of wire A is three times greater than that of wire B. (ii) What is the ratio of the radius of A to that of B

(a) 4 R (b) 2 R (c) R (d) 1/2R (e) 1/4R

8 0
2 years ago
A roller coaster has a mass of 450 kgIt sits at the top of a hill with height 49 m. If it drops from this hill, how fast is it g
fgiga [73]

The speed of the roller coater at the bottom of the hill is 31 m/s.

<h3>Speed of the roller coater at the bottom of the hill</h3>

Apply the principle of conservation of mechanical energy as follows;

K.E(bottom) = P.E(top)

¹/₂mv² = mgh

v² = 2gh

v = √2gh

where;

  • v is the speed of the coater at bottom hill
  • h is the height of the hill
  • g is acceleration due to gravity

v = √(2 x 9.8 x 49)

v = 31 m/s

Thus, the speed of the roller coater at the bottom of the hill is 31 m/s.

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6 0
2 years ago
If the mass of a planet is 0.231 mE and its radius is 0.528 rE, estimate the gravitational field g at the surface of the planet.
crimeas [40]

Answer:

8.1 m/s^2

Explanation:

The strength of the gravitational field at the surface of a planet is given by

g=\frac{GM}{R^2} (1)

where

G is the gravitational constant

M is the mass of the planet

R is the radius of the planet

For the Earth:

g_E = \frac{GM_E}{R_E^2}=9.8 m/s^2

For the unknown planet,

M_X = 0.231 M_E\\R_X = 0.528 R_E

Substituting into the eq.(1), we find the gravitational acceleration of planet X relative to that of the Earth:

g_X = \frac{GM_X}{R_X^2}=\frac{G(0.231M_E)}{(0.528R_E)^2}=\frac{0.231}{0.528^2}(\frac{GM_E}{R_E^2})=0.829 g_E

And substituting g = 9.8 m/s^2,

g_X = 0.829(9.8)=8.1 m/s^2

3 0
3 years ago
To use Faraday's law for this problem, you will need to construct a suitable loop, around which you will integrate the electric
VikaD [51]

Answer:

a. xy

Explanation:

The Faraday's law of induction can be used to express the relationship between the electric field line integral and the magnetic flux rate change in a closed loop. In order to ensure that the relationship between the two variables is equivalent to zero, the integration should be conducted on the xy plane. The correct option is option a.

6 0
4 years ago
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