Answer:
a)
Explanation:
- A block sliding down an inclined plane, is subject to two external forces along the slide.
- One is the component of gravity (the weight) parallel to the incline.
- If the inclined plane makes an angle θ with the horizontal, this component (projection of the downward gravity along the incline, can be written as follows:
(taking as positive the direction of the movement of the block)
- The other force, is the friction force, that adopts any value needed to meet the Newton's 2nd Law.
- When θ is so large, than the block moves downward along the incline, the friction force can be expressed as follows:
- The normal force, adopts the value needed to prevent any vertical movement through the surface of the incline:
- In equilibrium, both forces, as defined in (1), (2) and (3) must be equal in magnitude, as follows:
- As the block is moving, if the net force is 0, according to Newton's 2nd Law, the block must be moving at constant speed.
- In this condition, the friction coefficient is the kinetic one (μk), which can be calculated as follows:
Where is the multiple choice
Answer:
The wavelenght is λ= 6 * 10⁻⁴m.
Explanation:
v= 1500 m/s
f= 2.5 MHz = 2.5 *10⁶ Hz
λ=v/f
λ= 6 * 10⁻⁴ meters
It all depends. on what kind of link your on like a hill flate serface what it has to do with its wave length find the wave lenth and you then can find your anwser hope i helped
Answer:
(a) 2.5 cm
(b) Yes
Solution:
As per the question:
Mass of Uranium-235 ion, m =
Mass of Uranium- 238, m' =
Velocity, v =
Magnetic field, B = 0.250 T
q = 3e
Now,
To calculate the path separation while traversing a semi-circle:
The radius of the ion in a magnetic field is given by:
R =
Now,
By putting suitable values in the above eqn:
(b) Since the order of the distance is in cm, thus clearly this distance is sufficiently large enough in practical for the separation of the two uranium isotopes.