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Temka [501]
3 years ago
7

How many nuclear power plants exist in new jersey?

Physics
2 answers:
GuDViN [60]3 years ago
4 0
Nuclear power plants in New Jersey are:
- Hope Creek,
- Oyster Creek,
- Salem.
Oyster Creek is the oldest. It was built in 1969. Salem was built in 1977 and 1979 ( the 2nd unit ). Hope Creek was built in 1986.
Answer: There are 3 nuclear plants in New Jersey.
leva [86]3 years ago
4 0
Five nuclear power plants exist in New Jersey 
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g A meteoroid is in a circular orbit 600 km above the surface of a distant planet. The planet has the same mass as Earth but has
Nikitich [7]

Answer:

Explanation:

gravitational acceleration of meteoroid

=  GM / R²

M is mass of planet , R is radius of orbit of meteoroid from the Centre of the planet .

R = (.9 x 6370 + 600 )x 10³ m

= 6333 x 10³ m

M , mass of the planet = 5.97 x 10²⁴ kg .

gravitational acceleration of meteoroid

=  GM / R²

=  (6.67 x 10⁻¹¹ x 5.97 x 10²⁴ kg  / (6333 x 10³ m)²

9.92m/s²

3 0
3 years ago
Which can happen during a physical change?
4vir4ik [10]
C.<span>Molecules can move more rapidly and freely and change states.
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3 0
3 years ago
A long, thin rod parallel to the y-axis is located at x = - 1 cm and carries a uniform positive charge density λ = 1 nC/m . A se
zheka24 [161]

Answer:

The electric field at origin is 3600 N/C

Solution:

As per the question:

Charge density of rod 1, \lambda = 1\ nC = 1\times 10^{- 9}\ C

Charge density of rod 2, \lambda = - 1\ nC = - 1\times 10^{- 9}\ C

Now,

To calculate the electric field at origin:

We know that the electric field due to a long rod is given by:

\vec{E} = \frac{\lambda }{2\pi \epsilon_{o}{R}

Also,

\vec{E} = \frac{2K\lambda }{R}                  (1)

where

K = electrostatic constant = \frac{1}{4\pi \epsilon_{o} R}

R = Distance

\lambda = linear charge density

Now,

In case, the charge is positive, the electric field is away from the rod and towards it if the charge is negative.

At x = - 1 cm = - 0.01 m:

Using eqn (1):

\vec{E} = \frac{2\times 9\times 10^{9}\times 1\times 10^{- 9}}{0.01} = 1800\ N/C

\vec{E} = 1800\ N/C     (towards)

Now, at x = 1 cm = 0.01 m :

Using eqn (1):

\vec{E'} = \frac{2\times 9\times 10^{9}\times - 1\times 10^{- 9}}{0.01} = - 1800\ N/C

\vec{E'} = 1800\ N/C     (towards)

Now, the total field at the origin is the sum of both the fields:

\vec{E_{net}} = 1800 + 1800 = 3600\ N/C

7 0
3 years ago
A small, closed chamber of gas is heated. When the gas in the chamber expands,it does 5 J of work on a piston. The gas has an in
Anestetic [448]

Given:

Work done, W = 5 J

Initial energy = 8J

Final energy = 30J

Let's determine if the work done have a positive or nrgative value.

Appy the equation for the first lae of thermodynamics:

\Delta U=Q-W

Where:

U is the change in internal energy

Q is the added heat

W is the work done

To find the work done here, we have:

Rewrite the formula for W

W=Q-\Delta U

Where:

ΔU = 30J - 8J = 22J

Q = 5J

Thus, we have:

\begin{gathered} W=5J-22J \\  \\ W=-17J \end{gathered}

Therefore, the work done here is -17J.

This means the work done in this scenario has a negative value.

ANSWER:

The work done in this scenario has a negative value

3 0
1 year ago
A 20 kg bike accelerates at 10 m/s2. With what force was the person pedaling if friction
Molodets [167]
Look it up plz cuz like I’m slow so
4 0
3 years ago
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