Answer this ASAP please

Mathematics

1 answer:

Vikentia [17]2 years ago

3 0

IM SORRYYY

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Formulas

Olegator [25]

The second option.......

7 0

2 years ago

Heyy can you please help me posted picture of question

vichka [17]

We can use quadratic formula to determine the roots of the given quadratic equation.

The quadratic formula is:

$x= \frac{-b+- \sqrt{ b^{2} -4ac} }{2a}$

b = coefficient of x term = 4
a = coefficient of squared term = 1
c = constant term = 7

Using the values, we get:

$x= \frac{-4+- \sqrt{16-4(1)(7)} }{2(1)} \\ \\ 
x= \frac{-4+- \sqrt{-12} }{2} \\ \\ 
x= \frac{-4+-2 \sqrt{-3} }{2} \\ \\ 
x= -2+- \sqrt{-3}$

So, the correct answer to this question is option A

7 0

3 years ago

What is the remainder of f(x)=x^4-2x^3-27x^2-9x+18 when divided by binomial x+4

givi [52]

Answer:

The remainder will be 6.

Step-by-step explanation:

We have the function:

$f(x)=x^4-2x^3-27x^2-9x+18$

And we want to find the remainder after it is divided by the binomial:

$x+4$

We can use the Polynomial Remainder Theorem. According to the PRT, if we have a polynomial P(x) being divided by a binomial in the form (x - a), then the remainder will be given by P(a).

Here, our divisor is (x + 4). We can rewrite this as (x - (-4)).

Therefore, a = -4.

Then according to the PRT, the remainder will be:

$f(-4)=(-4)^4-2(-4)^3-27(-4)^2-9(-4)+18=6$