Answer:
a
Since the integral has an infinite discontinuity, it is a Type 2 improper integral
b
Since the integral has an infinite interval of integration, it is a Type 1 improper integral
c
Since the integral has an infinite interval of integration, it is a Type 1 improper integral
d
Since the integral has an infinite discontinuity, it is a Type 2 improper integral
Step-by-step explanation:
Considering a

Looking at this we that at x = 3 this integral will be infinitely discontinuous
Considering b

Looking at this integral we see that the interval is between
which means that the integral has an infinite interval of integration , hence it is a Type 1 improper integral
Considering c

Looking at this integral we see that the interval is between
which means that the integral has an infinite interval of integration , hence it is a Type 1 improper integral
Considering d

Looking at the integral we see that at x = 0 cot (0) will be infinity hence the integral has an infinite discontinuity , so it is a Type 2 improper integral
Answer:
x = 6
y = 2
Explanation:
To solve the system using elimination, we need to multiply the second equation by -1, so the second equation is equivalent to:
x - 9y = -12
-1 (x - 9y) = -1 (-12)
-x + 9y = 12
Then, we can sum this equation and the first equation. So:
5x - 9y = 12
-x + 9y = 12
4x + 0 = 24
So, we can solve for x, as:
4x = 24
4x/4 = 24/4
x = 6
Then, we can replace x by 6 on the first equation and solve for y, so:
5x - 9y = 12
5(6) - 9y = 12
30 - 9y = 12
30 - 9y - 30 = 12 - 30
-9y = -18
-9y/(-9) = -18/(-9)
y = 2
Therefore, the solution of the system is x = 6 and y = 2
Answer:
Step-by-step explanation:
3/7 * 11/4=1.17857142857
{(9)(9/256)}^3/2=
(81/256)^3/2=
0.031676352/2=
0.015838176