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3 years ago

If a radiation source has a wavelength of 4.76 x 10-6 m, then what is its frequency?

Chemistry

1 answer:

ladessa [460]3 years ago

8 0

Answer: 6.3 * 10^15

Explanation:

wavelength = speed of light / frequency

so rewriting the equation gives frequency = speed of light / wavelength

so 3.0 *10^10 / 4.76 * 10^-6 = 6.3 * 10^15

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g You observed the formation of several precipitates in the Reactions in Solution lab exercise. Identify the precipitate in each

RUDIKE [14]

Answer:

For a: Lead iodide is a yellow precipitate.

For b: Barium sulfate is a white precipitate.

For c: Ferric hydroxide is a brown precipitate.

For d: Copper (II) hydroxide is a blue precipitate.

Explanation:

Precipitation reaction is defined as the reaction where a solid precipitate (solid substance) is formed at the end of the reaction. It is insoluble in water.

For the given options:

For (a):

The chemical reaction between KI and lead (II) nitrate follows:

$2KI(aq)+Pb(NO_3)_2(aq)\rightarrow PbI_2(s)+2KNO_3(aq)$

The iodide of lead is generally insoluble in water. Thus, lead iodide is a yellow precipitate.

For b:

The chemical reaction between barium chloride and sulfuric acid follows:

$BaCl_2(aq)+H_2SO_4(aq)\rightarrow BaSO_4(s)+2HCl(aq)$

The sulfate of barium is insoluble in water. Thus, barium sulfate is a white precipitate.

For c:

The chemical reaction between NaOH and ferric chloride follows:

$3NaOH(aq)+FeCl_3(aq)\rightarrow Fe(OH)_3(s)+3NaCl(aq)$

The hydroxide of iron is insoluble in water. Thus, ferric hydroxide is a brown precipitate.

For d:

The chemical reaction between NaOH and copper sulfate follows:

$CuSO_4+2NaOH\rightarrow Cu(OH)_2+Na_2SO_4$

The hydroxide of copper is insoluble in water. Thus, copper (II) hydroxide is a blue precipitate.

6 0

2 years ago

2) Which of the following statements best describes an element?

mixas84 [53]

Answer:

Explanation:

The answer woul be E because elements are made of one type of atoms

3 0

3 years ago

Read 2 more answers

Enter your answer in the provided box. an aqueous solution containing 10 g of an optically pure substance was diluted to 500 ml

sladkih [1.3K]

Answer:

[α] = -77.5° / $\frac{\textup{dm-g}}{\textup{mL}}$

Explanation:

Given;

Mass of optically pure substance in the solution = 10 g

Volume of water = 500 mL

Length of the polarimeter, l = 20 cm = 20 × 0.1 dm = 2 dm

measured rotation = - 3.10°

Now,

The specific rotation ( [α] ) is given as:

[α] = $\frac{\alpha}{c\times l}$

here,

α is the measured rotation = -3.10°

c is the concentration

c = $\frac{\textup{Mass of optically pure substance in the solution}}{\textup{Volume of water}}$

c = $\frac{10}{500}$

c = 0.02 g/mL

on substituting the values, we get

[α] = $\frac{-3.10^o}{0.02\times2}$

[α] = -77.5° / $\frac{\textup{dm-g}}{\textup{mL}}$

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A 4o kg skier starts at the top of a 12 meter high slope at the bottom she is traveling 10 m/s how much energy does she lose to

allsm [11]

I think the answer is b because that is true

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What occurs when ions from the the sun strike air molecules

damaskus [11]

Auroras occur when ions from the Sun strike air molecules, causing them to give off bright colors of light.-google

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