All categories

3 years ago

A green powder was placed into a beaker of water. After it was stirred

Chemistry

1 answer:

bekas [8.4K]3 years ago

7 0

Answer:

A solution was NOT formed.

Explanation:

For a solution to be formed, the green powder would need to dissolve in the water to form a homogenous mixture. But since the water was cloudy and had lumps of the green powder, it means that the powder did not dissolve, but instead remained insoluble.

You might be interested in

The following reaction shows the process of rusting. 4Fe + 3O2= 2Fe2O3 This chemical reaction should be classified as _____.

andrezito [222]

This is a synthesis reaction, where 2 reactants combine to form a single product.

In decomposition, 1 reactant splits into 2 products.
In single replacement, one element swaps with another, in the form A + BC = B + AC.
In double displacement two elements swap, in the form AB + CD = AD + CB
In neutralization (a kind of double displacement), an acid and a base react to form water and a salt.

5 0

3 years ago

Read 2 more answers

a 2.7 L of N2 is collected at 121kpa and 288 K . if the pressure increases to 202 kpa and the temperature rises to 303 K , what

jok3333 [9.3K]

Answer:

The gas will occupy a volume of 1.702 liters.

Explanation:

Let suppose that the gas behaves ideally. The equation of state for ideal gas is:

$P\cdot V = n\cdot R_{u}\cdot T$ (1)

Where:

$P$ - Pressure, measured in kilopascals.

$V$ - Volume, measured in liters.

$n$ - Molar quantity, measured in moles.

$T$ - Temperature, measured in Kelvin.

$R_{u}$ - Ideal gas constant, measured in kilopascal-liters per mole-Kelvin.

We can simplify the equation by constructing the following relationship:

$\frac{P_{1}\cdot V_{1}}{T_{1}} = \frac{P_{2}\cdot V_{2}}{T_{2}}$ (2)

Where:

$P_{1}$ , $P_{2}$ - Initial and final pressure, measured in kilopascals.

$V_{1}$ , $V_{2}$ - Initial and final volume, measured in liters.

$T_{1}$ , $T_{2}$ - Initial and final temperature, measured in Kelvin.

If we know that $P_{1} = 121\,kPa$ , $P_{2} = 202\,kPa$ , $V_{1} = 2.7\,L$ , $T_{1} = 288\,K$ and $T_{2} = 303\,K$ , the final volume of the gas is:

$V_{2} = \left(\frac{T_{2}}{T_{1}} \right)\cdot \left(\frac{P_{1}}{P_{2}} \right)\cdot V_{1}$

$V_{2} = 1.702\,L$

The gas will occupy a volume of 1.702 liters.

6 0

3 years ago

A chemical change is like a physical change because no new substance is formed. Agree or DIsagree and reason why

aleksandrvk [35]

I disagree, because a physical change changes the form, and a chemical change is a process where one or more substances are altered into new substances.

5 0

3 years ago

What are the covalent bonds called that form between atoms of different electronegativities?

ZanzabumX [31]

Polar bonds are formed between atoms of different electronegativities.

5 0

3 years ago

What equals the molar mass of a element

galina1969 [7]

Molar mass is the given substance divided by the amount of that substance, measured in g/mol.

Example: titanium atomic mass is 47.88 amu or 47.88 g/mol. In 47.88 grams of titanium there is 1 mole, or 6.022 x 10^23 titanium atoms.

7 0

3 years ago