Our emotions always tell us the truth about ourselves according to our

4. Alcohol makes me spontaneous and funny, which makes people like me.

weeeeeb [17]

Answer:

The last one.

Explanation:

It shows how this person thinks others like them when they drink. So that's an example of unspoken peer pressure. That's also a reason they think they should drink. ''makes me spontaneous and funny''.

Hope this helps :)

7 0

3 years ago

What is the role of health in the activities of population environment and development in points

kow [346]

Answer:

The importance of development efforts for the country's progress cannot be overstated. Agriculture, industry operation, electricity production, tourism, road construction, and other development activities are crucial for the country since they help promote income-generating activities. Economic progress can be seen in these works. People are employed as a result of such development initiatives. They hone their skills.

6 0

3 years ago

Differentiate the following functions (i) x(1+x)^3

statuscvo [17]

Answer:

$\displaystyle y' = (1 + x)^2(4x + 1)$

General Formulas and Concepts:

Algebra I

Terms/Coefficients
Functions
Function Notation
Factoring

Calculus

Derivatives

Derivative Notation

Derivative Property [Addition/Subtraction]: $\displaystyle \frac{d}{dx}[f(x) + g(x)] = \frac{d}{dx}[f(x)] + \frac{d}{dx}[g(x)]$

Basic Power Rule:

f(x) = cxⁿ
f’(x) = c·nxⁿ⁻¹

Derivative Rule [Product Rule]: $\displaystyle \frac{d}{dx} [f(x)g(x)]=f'(x)g(x) + g'(x)f(x)$

Derivative Rule [Chain Rule]: $\displaystyle \frac{d}{dx}[f(g(x))] =f'(g(x)) \cdot g'(x)$

Explanation:

Step 1: Define

Identify

y = x(1 + x)³

Step 2: Differentiate

Product Rule [Derivative Rule - Chain Rule]: $\displaystyle y' = \frac{d}{dx}[x] \cdot (1 + x)^3 + x \cdot \frac{d}{dx}[(1 + x)^3] \cdot \frac{d}{dx}[1 + x]$
Derivative Property [Addition/Subtraction]: $\displaystyle y' = \frac{d}{dx}[x] \cdot (1 + x)^3 + x \cdot \frac{d}{dx}[(1 + x)^3] \cdot (\frac{d}{dx}[1] + \frac{d}{dx}[x])$
Basic Power Rule: $\displaystyle y' = x^{1 - 1} \cdot (1 + x)^3 + x \cdot 3(1 + x)^{3 - 1} \cdot (0 + x^{1 - 1})$
Simplify: $\displaystyle y' = (1 + x)^3 + 3x(1 + x)^2$
Factor: $\displaystyle y' = (1 + x)^2 \bigg[ (1 + x) + 3x \bigg]$
Combine like terms: $\displaystyle y' = (1 + x)^2(4x + 1)$

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Derivatives

Book: College Calculus 10e

5 0

3 years ago

Why do you think it is so hard for people to get help for themselves?

ANEK [815]

It's hard for people to get help for themselves because they are embarrassed or afraid. Many people are scared of being judged or getting rejected so they don't want to get help. If someone asks them if they need help, they might say yes but otherwise, they wouldn't ask unless they know that nothing would happen to them, but even then, they would rather not ask.

8 0

3 years ago

What major factor contributes to overconsumption of sweets, sodas and fruit drinks, alcoholic beverages, and salty snacks?

KATRIN_1 [288]

Those things usually contain kasine which is known to have addictive properties

7 0

3 years ago