The number of Atoms must be the same on both sides
Answer:
2.5 Hz
Explanation:
Formula for the given question is:
Velocity= frequency X Wavelength.
v= f X λ.
25 = 10 X f
f= 2.5 Hz
When any atom loses two charged particles, it becomes an ion, with a charge opposite of the particles it lost. Ions will attempt to join up with other ions in ionic bonds, held together by the opposite charges of the atoms.
Answer:
(4) Water, stirring, and filtering
Explanation:
The added water will dissolve the sugar but not the sand. When you filter the mixture, the sand will be trapped in the filter paper and the dissolved sugar will pass through the pores of the paper.
(1) and (2) are wrong. You don't separate a mixture of sugar and sand by adding more sand. Furthermore, neither substance will boil at 100 °C.
(3) is wrong. You can dissolve the sugar in water but, if you boil the water away, the sugar and sand will still be together.
Explanation:
The weak intermolecular forces which can arise either between nucleus and electrons or between electron-electron are known as dispersion forces. These forces are also known as London dispersion forces and these are temporary in nature.
Dipole-dipole interactions are defined as the interactions that occur when partial positive charge on an atom is attracted by partial negative charge on another atom.
When a polar molecules produces a dipole on a non-polar molecule through distribution of electrons then it is known as dipole-induced forces.
Hydrogen bonding is defined as a bonding which exists between a hydrogen atom and an electronegative atom like O, N and F.
Chemical formula of acetone is 
. Due to the presence of oxygen atom there will be partial positive charge on carbon and a partial negative charge on oxygen atom. Hence, dipole-dipole forces will exist in a molecule of acetone.
Whereas hydrogen bonding will exist in a molecule of ethanol (
). Since, hydrogen atom is attached with electronegative oxygen atom.
Whereas London dispersion forces will also exist in both acetone and ethanol molecule.
