Question

2.0 moles of a monatomic ideal gas undergoes an isobaric process in which the temperature changes from 260 k to 320 k. what is the change in the internal energy of the gas?

Answer 1

The change in the internal energy of the gas is 1.5×10∧3 J.

The internal energy of an ideal gas is directly proportional to the temperature of the gas:

ΔE = 3/2 × n × R × ΔT

ΔT = 320 K - 260 K

ΔT = 60 K; change of the temperature

n = 2.0 mol: amount of a monatomic ideal gas

R = 8.1 J/mol×K;the ideal gas constant

ΔE = 3/2 × 2 mol × 8.1 J/mol×K × 60 K

ΔE = 1500 J

ΔE = 1.5×10∧3 J;  the internal energy of the gas

Isobaric process is a type of process in which the pressure of the system stays constant.

More about an isobaric process: brainly.com/question/28106078

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