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Kamila [148]
1 year ago
12

2.0 moles of a monatomic ideal gas undergoes an isobaric process in which the temperature changes from 260 k to 320 k. what is t

he change in the internal energy of the gas?
Chemistry
1 answer:
Alik [6]1 year ago
4 0

The change in the internal energy of the gas is 1.5×10∧3 J.

The internal energy of an ideal gas is directly proportional to the temperature of the gas:

ΔE = 3/2 × n × R × ΔT

ΔT = 320 K - 260 K

ΔT = 60 K; change of the temperature

n = 2.0 mol: amount of a monatomic ideal gas

R = 8.1 J/mol×K;the ideal gas constant

ΔE = 3/2 × 2 mol × 8.1 J/mol×K × 60 K

ΔE = 1500 J

ΔE = 1.5×10∧3 J;  the internal energy of the gas

Isobaric process is a type of process in which the pressure of the system stays constant.

More about an isobaric process: brainly.com/question/28106078

#SPJ4

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B. The substances that are formed

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a chemical reaction is a reaction that there's a formation of a new compound or substance.

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Answer:

Your statement is right.

Explanation:

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3 years ago
Water has a heat of fusion of about 300J/gram and a heat capacity for liquid water of a about 4J/gC. How much heat is needed to
amm1812

Answer:

The total heat required is 3.4 kJ

Explanation:

Calorimetry is the measurement and calculation of the amounts of heat exchanged by a body or a system.

There is a direct proportional relationship between heat and temperature. So, the amount of heat a body receives or transmits is determined by:

Q = c * m * ΔT

where Q is the heat exchanged by a body of mass m, made up of a specific heat substance c and where ΔT is the temperature variation.

In this case you know;

  • Q= ?
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Replacing:

Q= 4\frac{J}{g*C} *10 g * 10 C

Solving:

<em>Q1= 400 J</em>

On the other hand, you must determine the heat required to convert 0 ∘ C of ice to 0 ∘ C of liquid water by:

Q2=m*heat of fusion

Q2=10 g* 300 \frac{J}{g}

<em>Q2= 3,000 J</em>

The total heat required is:

Q= Q1 + Q2= 400 J + 3,000 J

Q= 3,400 J= 3.4 kJ (1 kJ= 1,000 J)

<u><em>The total heat required is 3.4 kJ</em></u>

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