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Gennadij [26K]
3 years ago
8

Which statements about peptide bonds are true? The formation of a peptide bond involves a dehydration reaction. Peptides are pol

ymers of proteins. A tetrapeptide contains five amino acid residues. Peptide bonds are ester linkages. A tripeptide contains three amino acid residues.
Chemistry
1 answer:
miv72 [106K]3 years ago
5 0

Answer:

- The formation of a peptide bond involves a dehydration reaction.

- A tripeptide contains three amino acid residues.

Explanation:

Peptide bonds are a type of covalent bonds that form between amino acid molecules. A peptide bond links two amino acids together by removing an hydrogen atom from the amine functional group (-NH2) and an hydroxyl (OH) from carboxylic functional group (-COOH) to release a water molecule. Hence, the formation of a peptide bond involves a dehydration reaction i.e loss of water.

This linking of one amino acid to another via a peptide bond forms a polypeptide and consequently a protein molecule. In other words, proteins are polymers of peptides. However, the linkage of three amino acids is called TRIPEPTIDE

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What is the theoretical yield of fluorenone if you oxidize 175 mg of fluorene?
My name is Ann [436]

Answer:

  • 602 mg of CO₂ and 94.8 mg of H₂O

Explanation:

The<em> yield</em> is measured by the amount of each product produced by the reaction.

The chemical formula of <em>fluorene</em> is C₁₃H₁₀, and its molar mass is 166.223 g/mol.

The <em>oxidation</em>, also know as combustion, of this hydrocarbon is represented by the following balanced chemical equation:

        2C_{13}H_{10}+31O_2\rightarrow 26CO_2+10H_2O

To calculate the yield follow these steps:

<u>1. Mole ratio</u>

          2molC_{13}H_{10}:31molO_2:26molCO_2:10molH_2O

<u />

<u>2. Convert 175mg of fluorene to number of moles</u>

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  • Number of moles = mass in grams / molar mass

  • \text{number of moles}=0.175g/166.223g/mol=0.0010528mol

<u>3. Set a proportion for each product of the reaction</u>

a) <u>For CO₂</u>

i) number of moles

         2molC_{10}H_{13}/26molCO_2=0.0010528molC_{10}H{13}/x

x=0.0010528molC_{10}H_{13}\times 26molCO_2/2molC_{10}H_{13}=0.013686molCO_2

ii) mass in grams

The molar mass of CO₂ is 44.01g/mol

  • mass = number of moles × molar mass
  • mass = 0.013686 moles × 44.01 g/mol = 0.602 g = 602mg

b) <u>For H₂O</u>

i) number of moles

0.0010528molC_{10}H_{13}\times10molH_2O/2molC_{10}H_{13}=0.00526molH_2O

ii) mass in grams

The molar mass of H₂O is 18.015g/mol

  • mass = number of moles × molar mass
  • mass = 0.00526 moles × 18.015 g/mol = 0.0948mg = 94.8 mg
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3 years ago
Read 2 more answers
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