The question is incomplete, here is the complete question:
What volume (mL) of the partially neutralized stomach acid having concentration 2M was neutralized by 0.01 M NaOH during the titration? (portion of 25.00 mL NaOH sample was used; this was the HCl remaining after the antacid tablet did it's job)
<u>Answer:</u> The volume of HCl neutralized is 0.125 mL
<u>Explanation:</u>
To calculate the concentration of acid, we use the equation given by neutralization reaction:
![n_1M_1V_1=n_2M_2V_2](https://tex.z-dn.net/?f=n_1M_1V_1%3Dn_2M_2V_2)
where,
are the n-factor, molarity and volume of acid which is HCl (Stomach acid)
are the n-factor, molarity and volume of base which is NaOH.
We are given:
![n_1=1\\M_1=2M\\V_1=?mL\\n_2=1\\M_2=0.01M\\V_2=25mL](https://tex.z-dn.net/?f=n_1%3D1%5C%5CM_1%3D2M%5C%5CV_1%3D%3FmL%5C%5Cn_2%3D1%5C%5CM_2%3D0.01M%5C%5CV_2%3D25mL)
Putting values in above equation, we get:
![1\times 2\times V_1=1\times 0.01\times 25\\\\V_1=\frac{1\times 0.01\times 25}{1\times 2}=0.125mL](https://tex.z-dn.net/?f=1%5Ctimes%202%5Ctimes%20V_1%3D1%5Ctimes%200.01%5Ctimes%2025%5C%5C%5C%5CV_1%3D%5Cfrac%7B1%5Ctimes%200.01%5Ctimes%2025%7D%7B1%5Ctimes%202%7D%3D0.125mL)
Hence, the volume of HCl neutralized is 0.125 mL
The correct answer is option B.
Research focused on how to cure cancer is an example of applied research.
The examples of basic research are :
A.) Research focused on how the human brain works
C.) Research focused on detecting life on other planets
D.) Research focused on human behavior
Applied research targets to solve specific human problems that have commercial value in the present day. Basic research is about understanding the fundamentals of science and nature, and it is essential to laying down the foundation of applied research.
Answer:is that a question problem or-
Explanation:
Answer:
![{ \rm{5CaC _{2}O _{4(aq)}+ 2KMnO _{4(aq)} + 8H _{2} SO _{4(aq)} → 5CaSO _{4(s)}+ 2Mn SO _{4(aq)}+ K _{2} SO _{4(s)} + 10CO _{2(g)} + 8H _{2} O _{l} }}](https://tex.z-dn.net/?f=%7B%20%5Crm%7B5CaC%20_%7B2%7DO%20_%7B4%28aq%29%7D%2B%202KMnO%20_%7B4%28aq%29%7D%20%2B%208H%20_%7B2%7D%20SO%20_%7B4%28aq%29%7D%20%20%E2%86%92%205CaSO%20_%7B4%28s%29%7D%2B%202Mn%20SO%20_%7B4%28aq%29%7D%2B%20K%20_%7B2%7D%20SO%20_%7B4%28s%29%7D%20%2B%2010CO%20_%7B2%28g%29%7D%20%20%2B%208H%20_%7B2%7D%20O%20_%7Bl%7D%20%7D%7D)
Explanation:
This is a redox reaction formed by combining two half equations.
Check the image above, sorry if my handwriting is poor :(
Answer:
V3− B) A nonmetal that gained three electrons
X− A) A nonmetal that gained one electron
Y+ C) A metal that lost one electron
Z3+ D) A metal that lost three electrons
Explanation:
As per the Octet rule, each atom must have eight electrons in its outermost shell.
The non-metals gain electrons while reacting to reach the configurations of noble gas as they possess lower Ionization ability and higher electro-negativity. Thus, they will have a negative charge(V3 -, X-)
Metals, on the other hand, lose electrons to reach a stable octet configuration due to the higher electro-positivity and lower electron affinity. Therefore, they will have a positive charge(Y+, Z3+).