Question

The table represents an exponential function. A 2-column table has 4 rows. The first column is labeled x with entries 1, 2, 3, 4. The second column is labeled y with entries three-halves, nine-eigths, StartFraction 27 Over 32 EndFraction, StartFraction 81 Over 128 EndFraction. What is the multiplicative rate of change of the function? Two-thirds Three-fourths Four-thirds Three-halves

Answer 1

Answer:

3/4

Step-by-step explanation:

x |  y

1  | 3/2

2 | 9/8

3 | 27/32

4 |  81/128

$\frac{\frac{9}{8}}{\frac{3}{2}}=\frac{9}{8} \div \frac{3}{2}=\frac{9}{8} \cdot \frac{2}{3}=\frac{18}{24}=\frac{18 \div 3}{24 \div 3}=\frac{6}{8}=\frac{6 \div 2}{8 \div 2}=\frac{3}{4}$

So the multiplicative rate of change of this function is $\frac{3}{4}$ .

Answer 2

Answer:

Option B.

Step-by-step explanation:

The given table is

x           y

1        $\frac{3}{2}$

2        $\frac{9}{8}$

3        $\frac{27}{32}$

4        $\frac{81}{128}$

We need to find the multiplicative rate of change of the function.

Let multiplicative rate of change is k, then

$k=\dfrac{a_2}{a_1}$

$k=\dfrac{\frac{9}{8}}{\frac{3}{2}}$

$k=\dfrac{9}{8}\times \dfrac{2}{3}$

$k=\dfrac{3}{4}$

Therefore, the correct option is B.