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myrzilka [38]
3 years ago
13

At Burnt Mesa Pueblo, archaeological studies have used the method of tree-ring dating in an effort to determine when prehistoric

people lived in the pueblo. Wood from several excavations gave a mean of (year) 1246 with a standard deviation of 42 years. The distribution of dates was more or less mound-shaped and symmetric about the mean. Use the empirical rule to estimate the following:
a. a range of years centered about the mean in which about 68% of the data (tree-ring dates) will be found between _______and _____ A.D.
b. a range of years centered about the mean in Which about Of the data (tree-ring dates) will be found between______ and ________ A.D.
c. a range of years centered about the mean in Which almost all the data (tree-ring dates) Will be found between_____ and A.D.
Mathematics
1 answer:
olya-2409 [2.1K]3 years ago
4 0

Answer:

(1204 ; 1288) ;

(1162 ; 1330) ;

(1120 ; 1372)

Step-by-step explanation:

Given that:

Mean, m = 1246 years

Standard deviation, s = 42 years

68% is within one standard deviation the mean ;

Therefore 68% equals ;

mean ± 1(standard deviation)

(1246 - 1(42)) ; (1246 + 1(42))

1204 ; 1288

B) b. a range of years centered 95% about the mean in Which about Of the data (tree-ring dates) will be found between______ and ________ A.D.

95% is within two standard deviation of the mean ;

Therefore 95% equals ;

mean ± 2(standard deviation)

(1246 - 2(42)) ; (1246 + 2(42)

(1246 - 84) ; (1246 + 84)

(1162 ; 1330)

c. a range of years centered about the mean in Which almost all the data (tree-ring dates) Will be found between_____ and A.D.

About 99.7% which is within 3 standard deviations of the mean

99.7% is within 3 standard deviations of the mean ;

Therefore ;

mean ± 3(standard deviation)

(1246 - 3(42)) ; (1246 + 3(42))

(1120 ; 1372)

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QUESTION 1  

If a function is continuous at x=a, then \lim_{x \to a}f(x)=f(a)  

Let us find the limit first,  

\lim_{x \to 4} \frac{x-4}{x+5}  

As x \rightarrow 4, x-4 \rightarrow 0,x+5 \rightarrow 9 and f(x) \rightarrow \frac{0}{9}=0  

\therefore \lim_{x \to 4} \frac{x-4}{x+5}=0  

Let us now find the functional value at x=4  

f(4)=\frac{4-4}{4+5} =\frac{0}{9}=0  

Since  

\lim_{x \to 4} f(x)=\frac{x-4}{x+5}=f(4), the function is continuous at a=4.  

QUESTION 2  

The correct answer is table 2. See attachment.


In this table the values of x approaches zero from both sides.


This can help us determine if the one sided limits are approaching the same value.

As we are getting closer and closer to zero from both sides, the function is approaching 2.


The values are also very close to zero unlike those in table 4.


The correct answer is B


QUESTION 3


We want to evaluate;


\lim_{x \to 1} \frac{x^3+5x^2+3x-9}{x-1}


using the properties of limits.


A direct evaluation gives \frac{1^3+5(1)^2+3(1)-9}{1-1}=\frac{0}{0}.


This indeterminate form suggests that, we simplify the function first.


We factor to obtain,


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We cancel common factors to get,


\lim_{x \to 1} (x+3)^2


=(1+3)^2=16


The correct answer is D



QUESTION 4

We can see from the table that as x approaches -2 from both sides, the function approaches -4


Hence the limit is -4.


See attachment


The correct answer is option A

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