45.00+4.00 < or = 74
(Sorry don’t have the sign)
Lmk if that helped
Answer:
Step-by-step explanation:
the first one is correct
Answer:
(3,2)
Step-by-step explanation:
Here's your given:
y = 4x - 10
y = 2
Because they both equal y, that means they equal each other:
2 = 4x - 10
Add 10 on both sides:
12 = 4x
Then, divide 4 on both sides:
3 = x
This represents the x coordinate.
Normally you would put this value into one of the equations to figure out y, but they already gave us that in the beginning:
y = 2
This represents the y coordinate.
Put the two values together to get: (3,2)
Answer:
Option 3 - 
Step-by-step explanation:
Given : Perpendicular to the line
; containing the point (4,4).
To Find : An equation for the line with the given properties ?
Solution :
We know that,
When two lines are perpendicular then slope of one equation is negative reciprocal of another equation.
Slope of the equation 
Converting into slope form
,
Where m is the slope.


The slope of the equation is 
The slope of the perpendicular equation is 
The required slope is 

The required equation is 
Substitute point (x,y)=(4,4)



Substitute back in equation,

Therefore, The required equation for the line is 
So, Option 3 is correct.