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2 years ago

7

SOCCER TRACK GOLF 112 74 59 # OF STUDENTS There are 450 7th graders at Lakeside Middle School. The chart above shows the number

that participate in a certain sport Find and fix the incorrect statement #1. About 55% of 7 graders do not play a sport #2: Of the students who play a sport, 24% play golf #3: Of the students who play a sport, 46% play soccer #4: About 16% of all 7 graders run track HURRYYYYYYYYYYYYY

1 answer:

enot [183]2 years ago

3 0

Answer: about 14% of the 7 grade don't play sports

Step-by-step explanation: i think

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A ball, dropped vertically, falls d metres in t seconds.

Sergio [31]

Answer:

455m

Step-by-step explanation:

We know that acceleration is acceleration due to gravity, which is 10m/s, and initial speed u=0m/s

Use the motion equation to find distance when t=10:

d=ut+(1/2)at²

d=0t+(1/2)(10)(10²)

d=500m

The distance travelled in the seven seconds following the first three = 500-45=455m

8 0

3 years ago

If 75 people attend a concert and tickets for adults cost $2.75 while tickets for children cost $2.25 and

Serhud [2]

Answer:

Adult = 39

Children = 36

Step-by-step explanation:

The total number of people = 75

Cost of adult ticket = $2.75

Cost of children ticket = $2.25

Total receipts = $188.25

Let the number of adult = x

Let the number of children = y

X + y = 75 ......equation (i)

(X × 2.75) + (y × 2.25) = 188.25

2.75x + 2.25y = 188.25.......equation (ii)

To find the numbe of adult and children that attended, we'll have to solve equation (i) and (ii) simultaneously.

From equation 1,

X + y = 75

X = 75 - y......equation(iii)

Put equation (iii) into equation (ii)

2.75*(75 - y) + 2.25y = 188.25

206.25 - 2.75y + 2.25y = 188.25

206.25 - 0.5y = 188.25

Collect liketerms

0.5y = 206.25 - 188.25

0.5y = 18

Y = 18 / 0.5

Y = 36

Put y = 36 into equation (i)

X + 36 = 75

X = 39

Therefore the number of adult is 39 while that of children is 36.

4 0

3 years ago

What are the x- and y-coordinates of point C, which partitions the directed line segment from A to B into the ratio 3:10? Round

Soloha48 [4]

Answer: on edge. it’s -2.6 and 5.2

Step-by-step explanation:

i just did it.

3 0

3 years ago

Read 2 more answers

City A had a population of 10000 in the year 1990. City A’s population grows at a constant rate of 3% per year. City B has a pop

Georgia [21]

Answer:

City A and city B will have equal population 25years after 1990

Step-by-step explanation:

Given

Let

$t \to$ years after 1990

$A_t \to$ population function of city A

$B_t \to$ population function of city B

<u>City A</u>

$A_0 = 10000$ ---- initial population (1990)

$r_A =3\%$ --- rate

<u>City B</u>

$B_{10} = \frac{1}{2} * A_{10}$ ----- t = 10 in 2000

$A_{20} = B_{20} * (1 + 20\%)$ ---- t = 20 in 2010

Required

When they will have the same population

Both functions follow exponential function.

So, we have:

$A_t = A_0 * (1 + r_A)^t$

$B_t = B_0 * (1 + r_B)^t$

Calculate the population of city A in 2000 (t = 10)

$A_t = A_0 * (1 + r_A)^t$

$A_{10} = 10000 * (1 + 3\%)^{10}$

$A_{10} = 10000 * (1 + 0.03)^{10}$

$A_{10} = 10000 * (1.03)^{10}$

$A_{10} = 13439.16$

Calculate the population of city A in 2010 (t = 20)

$A_t = A_0 * (1 + r_A)^t$

$A_{20} = 10000 * (1 + 3\%)^{20}$

$A_{20} = 10000 * (1 + 0.03)^{20}$

$A_{20} = 10000 * (1.03)^{20}$

$A_{20} = 18061.11$

From the question, we have:

$B_{10} = \frac{1}{2} * A_{10}$ and $A_{20} = B_{20} * (1 + 20\%)$

$B_{10} = \frac{1}{2} * A_{10}$

$B_{10} = \frac{1}{2} * 13439.16$

$B_{10} = 6719.58$

$A_{20} = B_{20} * (1 + 20\%)$

$18061.11 = B_{20} * (1 + 20\%)$

$18061.11 = B_{20} * (1 + 0.20)$

$18061.11 = B_{20} * (1.20)$

Solve for B20

$B_{20} = \frac{18061.11}{1.20}$

$B_{20} = 15050.93$

$B_{10} = 6719.58$ and $B_{20} = 15050.93$ can be used to determine the function of city B

$B_t = B_0 * (1 + r_B)^t$

For: $B_{10} = 6719.58$

We have:

$B_{10} = B_0 * (1 + r_B)^{10}$

$B_0 * (1 + r_B)^{10} = 6719.58$

For: $B_{20} = 15050.93$

We have:

$B_{20} = B_0 * (1 + r_B)^{20}$

$B_0 * (1 + r_B)^{20} = 15050.93$

Divide $B_0 * (1 + r_B)^{20} = 15050.93$ by $B_0 * (1 + r_B)^{10} = 6719.58$

$\frac{B_0 * (1 + r_B)^{20}}{B_0 * (1 + r_B)^{10}} = \frac{15050.93}{6719.58}$

$\frac{(1 + r_B)^{20}}{(1 + r_B)^{10}} = 2.2399$

Apply law of indices

$(1 + r_B)^{20-10} = 2.2399$

$(1 + r_B)^{10} = 2.2399$ --- (1)

Take 10th root of both sides

$1 + r_B = \sqrt[10]{2.2399}$

$1 + r_B = 1.08$

Subtract 1 from both sides

$r_B = 0.08$

To calculate $B_0$ , we have:

$B_0 * (1 + r_B)^{10} = 6719.58$

Recall that: $(1 + r_B)^{10} = 2.2399$

So:

$B_0 * 2.2399 = 6719.58$

$B_0 = \frac{6719.58}{2.2399}$

$B_0 = 3000$

Hence:

$B_t = B_0 * (1 + r_B)^t$

$B_t = 3000 * (1 + 0.08)^t$

$B_t = 3000 * (1.08)^t$

The question requires that we solve for t when:

$A_t = B_t$

Where:

$A_t = A_0 * (1 + r_A)^t$

$A_t = 10000 * (1 + 3\%)^t$

$A_t = 10000 * (1 + 0.03)^t$

$A_t = 10000 * (1.03)^t$

and

$B_t = 3000 * (1.08)^t$

$A_t = B_t$ becomes

$10000 * (1.03)^t = 3000 * (1.08)^t$

Divide both sides by 10000

$(1.03)^t = 0.3 * (1.08)^t$

Divide both sides by $(1.08)^t$

$(\frac{1.03}{1.08})^t = 0.3$

$(0.9537)^t = 0.3$

Take natural logarithm of both sides

$\ln(0.9537)^t = \ln(0.3)$

Rewrite as:

$t\cdot\ln(0.9537) = \ln(0.3)$

Solve for t

$t = \frac{\ln(0.3)}{ln(0.9537)}$

$t = 25.397$

Approximate

$t = 25$

7 0

3 years ago

Greta wants to make 5 pounds of a nut mix using peanuts and cashews. Her budget requires the mixture to cost her $6 per pound. P

Vinil7 [7]

Answer:

3 pounds of peanuts and 2 pounds of cashews

Step-by-step explanation:

Let x be the pounds of peanuts and y be the pounds of cashews

Greta wants to make 5 pounds of a nut mix using peanuts and cashews.

So, $x+y=5$ ----- A

Cost of 1 pound of peanuts = $4

Cost of x pounds of peanuts = 4x

Cost of 1 pound of cashews = $9

Cost of y pounds of cashews = 9y

Her budget requires the mixture to cost her $6 per pound

So, cost of mixture of x pounds of peanuts and y pounds of cashews is 6(x+y)

So, $4x+9y=6(x+y)$ --- B

Plot A and B

$x+y=5$ ---Blue

$4x+9x=6(x+y)$ ---Green

Refer the attached figure

Intersection point = (x,y)=(3,2)

Hence she should use 3 pounds of peanuts and 2 pounds of cashews

6 0

3 years ago