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Ksivusya [100]
3 years ago
5

Trig: solve for theta

Mathematics
1 answer:
Readme [11.4K]3 years ago
3 0

\\ \sf\longmapsto 5sin\theta-8=3sin\theta-9

\\ \sf\longmapsto 5sin\theta-3sin\theta=9+8

\\ \sf\longmapsto 2sin\theta=17

\\ \sf\longmapsto sin\theta=\dfrac{17}{2}

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Solve for c.<br><br> 3 − 7c − 20c = 7(–7c − 19) + 14c<br><br> c =
OleMash [197]

Answer:

\boxed{c = -17}

Step-by-step explanation:

=  > 3 - 7c - 20c = 7( - 7c - 19) + 14c \\  \\  =  > 3 - 27c = ( - 7c \times 7) - (7 \times 19) + 14c \\  \\  =  > 3 - 27c =  - 49c - 133 + 14c \\  \\  =  > 3 - 27c =  - 35c - 133 \\  \\  =  > 3 - 27c + 35c =  - 133 \\  \\  =  > 3  + 8c =  - 133 \\  \\  =  > 8c =  - 133 - 3 \\  \\  =  > 8c =  - 136 \\  \\  =  > c =  -  \frac{136}{8}  \\  \\  =  > c =  - 17

7 0
3 years ago
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What is the answer??<br>12=√160-r
babunello [35]
The answer is r=16 you have to square everything

6 0
2 years ago
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The amount of time workers spend commuting to their jobs each day in a large metropolitan city has a mean of 70 minutes and a st
Zepler [3.9K]

Answer:

At least 75% of these commuting times are between 30 and 110 minutes

Step-by-step explanation:

Chebyshev Theorem

The Chebyshev Theorem can also be applied to non-normal distribution. It states that:

At least 75% of the measures are within 2 standard deviations of the mean.

At least 89% of the measures are within 3 standard deviations of the mean.

An in general terms, the percentage of measures within k standard deviations of the mean is given by 100(1 - \frac{1}{k^{2}}).

In this question:

Mean of 70 minutes, standard deviation of 20 minutes.

Since nothing is known about the distribution, we use Chebyshev's Theorem.

What percentage of these commuting times are between 30 and 110 minutes

30 = 70 - 2*20

110 = 70 + 2*20

THis means that 30 and 110 minutes is within 2 standard deviations of the mean, which means that at least 75% of these commuting times are between 30 and 110 minutes

8 0
3 years ago
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Ipatiy [6.2K]
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4 0
3 years ago
A man flies a kite at a height of 15 ft. The wind is carrying the kite horizontally from the man at a rate of 5 ft./s. How fast
Misha Larkins [42]

Answer:

4.4 ft/s

Step-by-step explanation:

Height = 15ft

Rate= 5 ft/s

Distance from the man to the kite= 32ft

dh/dt = 5 ft/s

h = √32^2 - 15^2

h = √ 1025 - 225

h = √800

h = 28.28ft

D = √15^2 + h^2

dD/dt = 1/2(15^2 + h^2)^-1/2 (2h) dh/dt

= h(225 + h^2)^-1/2 dh/dt

= (h / √225 + h^2)5

= (28.28 / √225 + 28.28^2)5

= (28.28 / √1024.7584)5

= (28.28/32)5

= 0.88*5

= 4.4 ft/s

3 0
3 years ago
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