Answer:
2630 g
Step-by-step explanation:
From the given information:
Given that:
mean (μ) = 3750 g
Standard deviation (σ) = 500
Suppose the hospital officials demand special treatment with a percentage of lightest 3% (0.03) for newborn babies;
Then, the weight of birth that differentiates the babies that needed special treatment from those that do not can be computed as follows;
P(Z < z₁) = 0.03
Using the Excel Formula; =NORMSINV(0.03) = -1.88
z₁ = - 1.88
Using the test statistics z₁ formula:
By cross multiply, we have:
-1.88 × 500 = X - 3570
-940 = X - 3570
-X = -3570 + 940
-X = -2630
X = 2630 g
Hence, 2630 g is the required weight of birth that differentiates the babies that needed special treatment from those that do not
<span>k+12/k=8
Multiply k to remove the k in one side
</span><span>(k+12/k=8) (k)
</span>Therefore,
k^2+12k-8k=0
Thus,
The equations he must solved now is k^2-8+12=0
Answer:
So the second one is 3
The first one is 3
Step-by-step explanation:
You just divide the first one 4.02/1.34
The second one
1) 2x-5=1
2) add 5 on to both sides= 6
3) divide 2 by 6 = 3
We need to understand that the sign of your constant )that's your number -27) dictates how you factor. A + and - number multipled together yields a - number.
The middle term dictates what number is asigned the + or - signs. Knowing that are 6 is positive, the larger number will be assigned the positive sign.
So what to numbers multiply together to yield- 27, but have a difference of +6. +9 x -3 = -27
Therefore, we break our binomial up as follows, (x+9)(x-3)
-6 (-5) + 12
=30+12
=42
Hope this helps you!
