So close! But instead of adding the multiplication sign after the number you need to add them before. Good job though! :)
Answer:
[x+6y+2z][x²+(6y)²+(2z)²-6xy-12yz-2xz]
Step-by-step explanation:
x³+216y³+8z³-36xyz
x³+(6y)³+(2z)³-3×6×2×xyz
As we know
a³+b³+c³-3abc=(a+b+c)(a²+b²+c²-ab-bc-ca)
Let a=x
b=6y
c=2z
Now.
[x+6y+2z][(x²+(6y)²+(2z)²-x×6y-6y×2z-x×2z]
[x+6y+2z][x²+(6y)²+(2z)²-6xy-12yz-2xz]
Step-by-step explanation: because they need to have atleast 2500 calories a day
Answer:
t = -5
Step-by-step explanation:
Solve for t:
5 (t - 3) - 2 t = -30
Hint: | Distribute 5 over t - 3.
5 (t - 3) = 5 t - 15:
5 t - 15 - 2 t = -30
Hint: | Group like terms in 5 t - 2 t - 15.
Grouping like terms, 5 t - 2 t - 15 = (5 t - 2 t) - 15:
(5 t - 2 t) - 15 = -30
Hint: | Combine like terms in 5 t - 2 t.
5 t - 2 t = 3 t:
3 t - 15 = -30
Hint: | Isolate terms with t to the left hand side.
Add 15 to both sides:
3 t + (15 - 15) = 15 - 30
Hint: | Look for the difference of two identical terms.
15 - 15 = 0:
3 t = 15 - 30
Hint: | Evaluate 15 - 30.
15 - 30 = -15:
3 t = -15
Hint: | Divide both sides by a constant to simplify the equation.
Divide both sides of 3 t = -15 by 3:
(3 t)/3 = (-15)/3
Hint: | Any nonzero number divided by itself is one.
3/3 = 1:
t = (-15)/3
Hint: | Reduce (-15)/3 to lowest terms. Start by finding the GCD of -15 and 3.
The gcd of -15 and 3 is 3, so (-15)/3 = (3 (-5))/(3×1) = 3/3×-5 = -5:
Answer: t = -5
Answer:
None (x=∅)
Step-by-step explanation:
5(x - 3) + 6 = 5x - 10
5x-15+6 = 5x-10
-15+6+10=5x-5x
1 = 0
x = ∅
